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使用以下xml我只想返回<category domain="Portal Sub" value="Events">
节点中存在子元素的项目。linq to xml只选择具有特定元素的节点
我试着用下面的代码,但它仍然返回所有节点。 任何帮助将不胜感激,因为我似乎无法弄清楚如何获得只有子节点存在的项目。
<item guid="123">
<title>test1</title>
<category domain="Target">Business Decision Makers</category>
<category domain="Target">Individual Customers</category>
<category domain="Target">IT Decision Makers</category>
<category domain="Portal" value="IT Network">
<category domain="Portal Sub" value="Events">
<category domain="Portal Sub" value="Forum" />
</category>
</category>
</item>
<item guid="456">
<title>test2</title>
<category domain="Target">IT managers</category>
<category domain="Target">IT Professional</category>
<category domain="Portal" value="IT Network">
<category domain="Portal Sub" value="Events" />
</category>
</item>
var getFilteredItems = (from item in xdoc.Descendants("item")
where item.Descendants("category").Descendants("category").Any()
select new
{
etype = (from x in item.Elements("category").Elements("category")
where x.Attribute("value").Value == "Events"
select new
{
cctype = x.Descendants("category").Select(i => i.Attribute("value").Value ?? "")
}).First()
}).ToList();
感谢马丁,完美。我玩弄了属性值,但错过了Elements.Any部分。感谢您的快速帮助! – 2012-03-06 11:24:01