获取纬度，经度从地址

Question

我想通过输入地址来获得的纬度和经度， 下面的代码，我从here但在我的情况下被复制，而我经过详细地址，它给我的错误：

Caused by: java.lang.IllegalArgumentException: Illegal character in query at index 56: http://maps.google.com/maps/api/geocode/json?address=43 S BROADWAY, Pitman, New Jersey 。

public static void getLatLongFromAddress(String youraddress) { 
    String uri = "http://maps.google.com/maps/api/geocode/json?address=" + 
        youraddress + "&sensor=false"; 
    HttpGet httpGet = new HttpGet(uri); 
    HttpClient client = new DefaultHttpClient(); 
    HttpResponse response; 
    StringBuilder stringBuilder = new StringBuilder(); 

    try { 
     response = client.execute(httpGet); 
     HttpEntity entity = response.getEntity(); 
     InputStream stream = entity.getContent(); 
     int b; 
     while ((b = stream.read()) != -1) { 
      stringBuilder.append((char) b); 
     } 
    } catch (ClientProtocolException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 

    JSONObject jsonObject = new JSONObject(); 
    try { 
     jsonObject = new JSONObject(stringBuilder.toString()); 

     double lng = ((JSONArray)jsonObject.get("results")).getJSONObject(0) 
      .getJSONObject("geometry").getJSONObject("location") 
      .getDouble("lng"); 

     dobule lat = ((JSONArray)jsonObject.get("results")).getJSONObject(0) 
      .getJSONObject("geometry").getJSONObject("location") 
      .getDouble("lat"); 

     Log.d("latitude", lat); 
     Log.d("longitude", lng); 
    } catch (JSONException e) { 
     e.printStackTrace(); 
    } 
} 

Answer 1

您无法将空格传递给URL。 尝试用%20替换每个空间，你应该没问题。

String replaced = yourString.replace(" ", "%20"); 

更多信息：W3Schools

Characters allowed in a URL

How do I replace a character in a string in Java?

Answer 2

您需要指定地址的当前城市或位置引用任何字段的名称地址，格式字符串，然后你得到的纬度和像

`Geocoder geocoder = new Geocoder(this, Locale.getDefault()); List<Address> addresses = geocoder.getFromLocation(lat, lng, 1);` 

请试试这个：

private static JSONObject getLocationInfo(String address) 
{ 

    StringBuilder stringBuilder = new StringBuilder(); 
    try { 

    address = address.replaceAll(" ","%20");  

    HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false"); 
    HttpClient client = new DefaultHttpClient(); 
    HttpResponse response; 
    stringBuilder = new StringBuilder(); 


     response = client.execute(httppost); 
     HttpEntity entity = response.getEntity(); 
     InputStream stream = entity.getContent(); 
     int b; 
     while ((b = stream.read()) != -1) { 
      stringBuilder.append((char) b); 
     } 
    } catch (ClientProtocolException e) { 
     Log.i("getLocationInfo ClientProtocolException", e.toString()); 
    } catch (IOException e) { 

     Log.i("getLocationInfo IOException", e.toString()); 
    } 


    JSONObject jsonObject = new JSONObject(); 
    try { 
     jsonObject = new JSONObject(stringBuilder.toString()); 
    } catch (JSONException e) { 
     // TODO Auto-generated catch block 
     Log.i("getLocationInfo JSONException", e.toString()); 
    } 

    return jsonObject; 
} 

private static boolean getLatLong(JSONObject jsonObject) 
{ 

    try { 

     longitute = ((JSONArray)jsonObject.get("results")).getJSONObject(0).getJSONObject("geometry").getJSONObject("location").getDouble("lng"); 
     Log.i("Log1", longitute1+""); 
    latitude = ((JSONArray)jsonObject.get("results")).getJSONObject(0) 
      .getJSONObject("geometry").getJSONObject("location") 
      .getDouble("lat"); 
     Log.i("lat1", latitude1+""); 
    } catch (JSONException e) { 

     longitute=0; 
     latitude = 0; 
     Log.i("getLatLong", e.toString()); 
     return false; 

    } 

    return true; 
} 

或进一步的地理编码需要你：

Geocoder gcd = new Geocoder(context, Locale.getDefault()); 
List<Address> addresses = gcd.getFromLocation(lat, lng, 1); 
if (addresses.size() > 0) 
    System.out.println(addresses.get(0).getLocality()); 

希望这会帮助你。

Answer 3

应该编码 “youraddress” 像

String encodedYourAddress = URLEncoder.encode(youraddress, "UTF-8"); 

，并建立了所谓的URI作为

String uri = "http://maps.google.com/maps/api/geocode/json?address="+encodedYourAddress+"&sensor=false"; 

Answer 4

用途：

youraddress = youraddress.replaceAll("\\s", "+"); 
String uri = "http://maps.google.com/maps/api/geocode/json?address=" + 
       youraddress + "&sensor=false"; 

更换所有空格+，类似的方式谷歌确实。这就是我们在应用程序中使用的方式。

Answer 5

您可以使用此功能对于

public LatLng getLatLng(Context _context,String locn){ 
     Geocoder geocoder = new Geocoder(_context,Locale.getDefault()); 
     try{     
      List<Address> addresses = geocoder.getFromLocationName(locn, 5); 
      if(addresses.size()>0) 
      {     
       GeoPoint p=new GeoPoint((int)(addresses.get(0).getLatitude()*1E6),(int)(addresses.get(0).getLongitude()*1E6)); 
       Double plat= (double) (p.getLatitudeE6())/1E6; 
       Double plon =(double) (p.getLongitudeE6())/1E6; 
       LatLng lonlat=new LatLng(plat,plon); 
      } 
     } 
     catch (IOException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } 
     return lonlat;   
    } 

只是通过当前context并具有转换为LatLng。以上函数返回地址的LatLng值的地址作为String。

而且，你可以得到相应的纬度和经度值，因为一旦如下

double lat = lonlat.latitude; 
double lng = lonlat.longitude; 

Answer 6

我有同样的问题。我使用URLEncoder类来解决这个问题。

我想你应该编码您的搜索词，并把它放在URL一样，

String query = URLEncoder.encode(address, "utf-8"); 
HttpGet httpGet = new HttpGet(
       "http://maps.google.com/maps/api/geocode/json?address=" 
         + query + "&ka&sensor=false"); 

这是按照我的理解为我工作的最佳解决方案。