这是我想出了最终:
我通过自己的生成器基类实现,查找'对象'参数并尝试从该对象获取所需的参数。
//src/Blogger/BlogBundle/Resources/config/services.yml
parameters:
router.options.generator_base_class: Blogger\BlogBundle\Routing\Generator\UrlGenerator
//src/Blogger/BlogBundle/Routing/Generator/UrlGenerator.php
namespace Blogger\BlogBundle\Routing\Generator;
use Symfony\Component\Routing\Generator\UrlGenerator as BaseUrlGenerator;
use Doctrine\Common\Util\Inflector;
/**
* UrlGenerator generates URL based on a set of routes.
*
* @api
*/
class UrlGenerator extends BaseUrlGenerator
{
protected function doGenerate($variables, $defaults, $requirements, $tokens, $parameters, $name, $absolute)
{
if (isset($parameters['object']) && is_object($parameters['object'])) {
$object = $parameters['object'];
$parameters = array_replace($this->context->getParameters(), $parameters);
$tparams = array_replace($defaults, $parameters);
$requiredParameters = array_diff_key(array_flip($variables), $tparams);
$parameters = $this->getParametersFromObject(array_flip($requiredParameters), $object);
}
return parent::doGenerate($variables, $defaults, $requirements, $tokens, $parameters, $name, $absolute);
}
protected function getParametersFromObject($keys, $object)
{
$parameters = array();
foreach ($keys as $key) {
$method = 'get' . Inflector::classify($key);
if (method_exists($object, $method)) {
$parameters[$key] = $object->$method();
}
}
return $parameters;
}
}
现在我可以这样写:从对象,并会得到所需要的参数(ID,蛞蝓):{} {路径(博客} 'BBBundle_blog_show',{ '对象')} 。
我很想看到这个(肯定会清理我的代码位),但据我所知这是不可能的。 – MrGlass 2012-01-16 14:05:04