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我编码,我这里得到一个错误:这个lua编码有什么问题?
Ammo = 450
Rocket = 20
Money = 35041
--Can I attend this mission?
function attendMission()
if Ammo >= 400 or Rocket >= 35 and Money >= 30000 then
return Money = Money - 30000
Msg("Attending Mission\n")
Msg("You now have "..Money.." dollars\n")
else
Msg("You do not have the resources to attend this mission\n")
end
end
print(attendMission())
--Ammo Amount
function whatIsAmmo()
if Ammo > 0 then
print("You have "..Ammo.." Ammo")
else
Msg("You have no Ammo")
end
end
print(whatIsAmmo())
--Rocket Amount
function whatIsRocket()
if Rocket > 0 then
Msg("You have "..Rocket.." rockets")
else
Msg("You have no rockets")
end
end
print(whatIsRocket())
--Money Amount
function whatIsMoney()
if Money > 100000 then
Msg("You have "..Money.." dollars, wow your rich!")
elseif Money > 0 then
Msg("You have "..Money.." dollars")
else
Msg("You have no money")
end
end
print(whatIsMoney())
它说,有预计近期=结束。我一直在寻找一段时间,但我不知道如何解决它。我已经缩小了错误在这一部分,虽然:
function attendMission()
if Ammo >= 400 or Rocket >= 35 and Money >= 30000 then
return Money = Money - 30000
Msg("Attending Mission\n")
Msg("You now have "..Money.." dollars\n")
else
Msg("You do not have the resources to attend this mission\n")
end
end
在Lua中(与C和其他一些语言不同),赋值是一个语句,而不是表达式。 – 2014-12-11 00:58:53
好吧,我这样做了,但是现在我在'Msg'附近得到''end''(如果'在6号线关闭')' – laws16 2014-12-11 00:59:52
'return'也需要是块中的最后一个语句(至少在lua中5.1)。所以这必须是该区块的最后一行。尽管你可以使用'do return end'来强制一个块使其工作。 – 2014-12-11 01:00:25