无法创建类型“闭合式”的恒定值

“无法创建类型‘闭合式’的恒定值。只有原始类型（'如Int32，字符串和Guid'）支持在这种情况下。 “

是否有人知道如何解决它或解决方法。

PS。我使用LINQ到实体没有LINQ to SQL的

List<int> listint 
List<int> listintTwo 

    return (from oa in _entity.TableOne 
      join cc in _entity.TableTwo on oa.TableSix.ColumnOne equals cc.TableSix.ColumnOne 
      join os in _entity.TableThree on oa.TableThree.ColumnTwo equals os.ColumnTwo 
      join cs in _entity.TableTwotatus on cc.TableTwotatus.ColumnThree equals cs.ColumnThree 
      join app in _entity.TableFour on cc.TableFour.ColumnFour equals app.ColumnFour 
      join cl in _entity.TableFive on app.TableFive.ColumnFive equals cl.ColumnFive 
      where listint.Any(x =>x == cc.TableTwotatus.ColumnThree) 
      && listintTwo.Any(x => x == os.ColumnTwo) && cc.TableSix.ColumnOne == ColumnOne 
      select new TableFive {ColumnFive = cl.ColumnFive, CompanyName = cl.CompanyName}).ToList();

来源

2011-02-17 Eugene

试着改变你的来电Any(...)到Contains(...)

where listint.Contains(cc.TableTwotatus.ColumnThree) 
&& listintTwo.Contains(os.ColumnTwo) && ...

我敢肯定它具有引用加盟实体与你的问题lambda表达式（充当闭包）。

来源

2011-02-19 00:01:47

您无法查询具有复杂类型的实体。所以首先从EF获得结果，然后加入你的复杂类型。

List<int> listint 
List<int> listintTwo 

return (from oa in _entity.TableOne 
     join cc in _entity.TableTwo on oa.TableSix.ColumnOne equals cc.TableSix.ColumnOne 
     join os in _entity.TableThree on oa.TableThree.ColumnTwo equals os.ColumnTwo 
     join cs in _entity.TableTwotatus on cc.TableTwotatus.ColumnThree equals cs.ColumnThree 
     join app in _entity.TableFour on cc.TableFour.ColumnFour equals app.ColumnFour 
     join cl in _entity.TableFive on app.TableFive.ColumnFive equals cl.ColumnFive).ToList(). 
     where listint.Any(x =>x == cc.TableTwotatus.ColumnThree) 
     && listintTwo.Any(x => x == os.ColumnTwo) && cc.TableSix.ColumnOne == ColumnOne 
     select new TableFive {ColumnFive = cl.ColumnFive, CompanyName = cl.CompanyName}).ToList();</pre>

来源

2014-11-11 06:20:10 user1553525

无法创建类型“闭合式”的恒定值

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