我正在为一个灯泡制作班级,我必须让它处于开/关状态,不管是否烧坏,以及它的颜色。无论出于何种原因,我都能切换正确的东西,但是,我的toString打印出错误的答案,我无法弄清楚原因。我不习惯使用布尔值,所以我的代码可能不支持我的逻辑。有人可以帮忙吗?toString和布尔值
下面是代码:
public class Light
{
// Variables that will be initialized in the Light constructors.
private boolean on;
private boolean burntOut;
private String color = "";
// Default constructor that sets the bulb to on, not burnt out, and "white".
public Light()
{
on= true;
burntOut = false;
color = "white";
}
// This constructor sets the variable "on" to the parameter o. The burntOut
// variable is set to the parameter b. If burntOut
// is true, on is set to false, no matter what value is stored in o.
// The color variable is set to the parameter c only if c is "red", "green"
// or "blue". The constructor ignores the case of the value in c. If c holds
// any value other than "red", "green" or "blue", the constructor sets
// color to "white".
public Light(boolean o, boolean b, String c)
{
on = o;
burntOut=b;
if(burntOut=true){
on = false;
}
else{
on= o;
}
if(c.equalsIgnoreCase("red")){
color = "red";
}
if(c.equalsIgnoreCase("blue")){
color = "blue";
}
if (c.equalsIgnoreCase("green")){
color="green";
}
else {
color = "white";
}
}
// The toString method returns a String with the Light in the format:
// off red burnt out
// on green not burnt out
//
// Notice there is one space between "off"/"on" and the value for color,
// and a tab before the "burnt out" or "not burnt out".
public String toString()
{
String x ="";
if(on = true){
x+="on" + " ";
}
if(on = false){
x+= "off" + " ";
}
x+= color;
if (burntOut = false){
x+="\t" + "not burnt out";
}
if(burntOut = true){
x+= "\t" + "burnt out";
}
return x;
}
这里是一个测试项目让我跑展示我的结果:
> run Light
1.测试灯() * PASS :on设置正确(true) PASS:burntout设置正确(false) PASS:设置颜色正确地(白色) * FAIL:如预期的toString不起作用(在白色烧坏)
- 测试灯(布尔B,布尔O,串c) * PASS :上设置正确(假) PASS:burntOut正确(真)设置 PASS:颜色设置正确(绿色) *失败:的toString不能按预期工作(绿色烧坏)
'='用于分配一个值。 – Satya
'==',而不是'='。或者,更好的是,如果(上){...}其他{...}'。 –
那么有道理 –