2017-10-16 117 views
1

我正在构建一个简单的应用程序,我想从我的Arduino使用enc28j60发送GET请求到位于我的在线主机中的php脚本。除了从数据库中看不到任何东西外,一切看起来都很完美。使用enc28j60无法发送GET请求arduino使用enc28j60

引脚:

ENC SO - > Arduino的销12

ENC SI - > Arduino的销11

ENC SCK - > Arduino的销13

ENC CS - > Arduino的销10

ENC VCC - >的Arduino 3V3销

ENC GND - >甲rduino GND引脚

这里是Arduino的代码:

#include <EtherCard.h> 



#define PATH "index.php" 
#define VARIABLE "test" 

// ethernet interface mac address, must be unique on the LAN 
byte mymac[] = { 0x74,0x69,0x69,0x2D,0x30,0x31 }; 

const char website[] PROGMEM = "billyval-com.stackstaging.com"; 

byte Ethernet::buffer[700]; 
uint32_t timer; 
Stash stash; 

void setup() { 
    Serial.begin(57600); 
    Serial.println("\n[webClient]"); 

    if (ether.begin(sizeof Ethernet::buffer, mymac) == 0) 
    Serial.println("Failed to access Ethernet controller"); 
    if (!ether.dhcpSetup()) 
    Serial.println("DHCP failed"); 

    ether.printIp("IP: ", ether.myip); 
    ether.printIp("GW: ", ether.gwip); 
    ether.printIp("DNS: ", ether.dnsip); 

    if (!ether.dnsLookup(website)) 
    Serial.println("DNS failed"); 

    ether.printIp("SRV: ", ether.hisip); 
} 

void loop() { 
    ether.packetLoop(ether.packetReceive()); 

    if (millis() > timer) { 
    timer = millis() + 10000; 

    byte sd = stash.create(); 
    stash.print("variable="); 
    stash.print(VARIABLE); 
    stash.save(); 


      Stash::prepare(PSTR("GET http://$F/$F HTTP/1.1" "\r\n" 
        "Host: $F" "\r\n" 
        "Content-Length: $D" "\r\n" 
        "Content-Type: application/x-www-form-urlencoded; charset=UTF-8" "\r\n" 
        "\r\n" 
        "$H"), 
     website, PSTR(PATH), website, stash.size(), sd); 

    // send the packet - this also releases all stash buffers once done 
    ether.tcpSend(); 

    } 
} 

,这里是基本的PHP脚本:

<?php 

$link = mysqli_connect("xxxx", "xxx", "xxx", "xxx"); 
if(mysqli_connect_error()){ 
    die("database failed"); 
} 

if(isset($_GET['variable'])){ 

    $query = "INSERT INTO variables (variable) VALUES ('". $_GET['variable'] ."') "; 
    mysqli_query($link, $query); 

} 

?> 

这里是我从串口监视器采取:

[Web客户端]

IP:192.168.10.10

GW:XXX

DNS:XXX

SRV:XXX

然而,当我检查的基础我看不到任何东西插入。但是,如果我在浏览器中手动执行此操作,例如: billyval-com.stackstaging.com/index.php?variable=x我可以在数据库中看到插入的值(x)。 我改变了发布,但我不能看到任何改变。

我无法弄清楚问题出在哪里,如果有人能帮助我,我会在这里发布。

非常感谢。

+0

GET HTTP请求应该没有消息体。 –

+0

你可以更特别吗?我认为我必须从Stash :: prepare中删除一些东西? – kakavia

+0

https://www.w3schools.com/tags/ref_httpmethods.asp –

回答

0

GET的要求是不正常:

Stash::prepare(PSTR("GET http://$F/$F HTTP/1.1" "\r\n" 
    "Host: $F" "\r\n" 
    "Content-Length: $D" "\r\n" 
    "Content-Type: application/x-www-form-urlencoded; charset=UTF-8" "\r\n" 
    "\r\n" 
    "$H"), 
website, PSTR(PATH), website, stash.size(), sd); 

应该POST请求,你用应用程序/ x-WWW窗体-urlencoded。 POST更适合发送数据。

一个POST请求如下所示:

POST /index.php HTTP/1.1 
Host: billyval-com.stackstaging.com 
Connection: close 
Content-Length: 200 
Content-Type: application/x-www-form-urlencoded 

variable1=1&variable2=2 

将此应用于代码:

Stash::prepare(PSTR("POST /$F HTTP/1.1" "\r\n" 
    "Host: $F" "\r\n" 
    "Content-Length: $D" "\r\n" 
    "Content-Type: application/x-www-form-urlencoded" "\r\n" 
    "\r\n" 
    "$H"), 
PSTR(PATH), website, stash.size(), sd); 

此外,PHP代码需要改变:

if(isset($_POST['variable'])){ 

    $query = "INSERT INTO variables (variable) VALUES ('". $_POST['variable'] ."') "; 
    mysqli_query($link, $query); 

} 

而且, read this

相关问题