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我在解析和显示来自非常简单的xml文件的信息时遇到了问题。Android - 将XML解析为ArrayList
首先,我将XML文件存储在res/xml文件夹中。在文件夹我有一个XML文件名为jokes.xml,该文件的内容如下:
<?xml version="1.0" encoding="utf-8"?>
<resources>
<joke>This is a good joke.</joke>
<joke>This is a very nice good great joke.</joke>
<joke>Oh Yeah!</joke>
</resources>
我要分析此文件,所有的笑话存储到一个ArrayList和获得一个随机之一显示。我的代码如下:
public class MainActivity extends Activity {
private TextView texto;
private int i = 0;
private String[] arrayJokes;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
texto = (TextView) findViewById(R.id.textView1);
XmlResourceParser joke = getResources().getXml(R.xml.jokes);
try {
while(joke.getEventType() != XmlResourceParser.END_DOCUMENT){
if(joke.getEventType() == XmlResourceParser.START_TAG){
String s = joke.getName();
if(s.equals("joke")){
arrayJokes[i] = joke.getAttributeValue(null, "joke");
i++;
}
}
}
} catch (XmlPullParserException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
//takes random id from the array
Random generator = new Random();
int rnd = generator.nextInt(arrayJokes.length);
String j = arrayJokes[rnd];
texto.setText(j);
}
}
问题是我只得到一个空白页。任何想法我做错了什么?
由于提前, 克劳迪奥