我想在android中显示数学方程,我发现这个https://github.com/kexanie/MathView这是工作得很好,但在这个代码从哪里可以得到方程的字符串tex。我试图将一个方程转换为使用单词16的乳胶格式,但是当我将转换的乳胶字符串替换为原始字符串(MainActivity中的字符串tex)时,而不是显示的公式显示时,乳胶字符串会按原样显示。在android中显示数学方程
第一MainActivity代码显示公式完全
public class MainActivity extends AppCompatActivity {
MathView formula_two;
String tex = "This come from string. You can insert inline formula:" +
" \\(ax^2 + bx + c = 0\\) " +
"or displayed formula: $$\\sum_{i=0}^n i^2 = \\frac{(n^2+n)(2n+1)}{6}$$";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
protected void onResume() {
super.onResume();
formula_two = (MathView) findViewById(R.id.formula_two);
formula_two.setText(tex);
}
}
这是MainActivity中,我更换了TEX字符串我的字符串
public class MainActivity extends AppCompatActivity {
MathView formula_two;
String tex = "\\begin{document}\n" +
"\n" +
"%\\selectlanguage{english} %%% remove comment delimiter ('%') and select language if required\n" +
"\n" +
"\n" +
"\\noindent ${\\left(x+a\\right)}^n=\\int^n_{k=0}{\\left(\\genfrac{}{}{0pt}{}{n}{k}\\right)x^ka^{n-k}}$ this is a test to check latex format ${\\left(1+x\\right)}^n=1+\\frac{nx}{1!}+\\frac{n\\left(n-1\\right)x^2}{2!}+\\dots $\n" +
"\n" +
"\\noindent \n" +
"\n" +
"\n" +
"\\end{document}";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
protected void onResume() {
super.onResume();
formula_two = (MathView) findViewById(R.id.formula_two);
formula_two.setText(tex);
}
}
我肯定做错了什么的将数学公式转换成tex格式。如何可以完美地转换它我试图 搜索一个很好的教程,但没有找到任何。任何帮助将 赞赏