ListView的公共ArrayAdapter

Question

参考下面的代码。我想知道为什么我需要放入一个对象而不是所有的字符串中的对象。此代码来自自定义ListView适配器。

public ArrayAdapter (Context context, int textViewResourceId, T[] objects)

做工精细

public ListViewAdapter(Context context, String[] first, String[] second, String[] third) { 
      super(context, R.layout.listview_item, first); 
      this.context = context; 
      this.first = first; 
      this.second = second; 
      this.third = third; 
     } 

错误，如果我这样做。

public ListViewAdapter(Context context, String[] first, String[] second, String[] third) { 
     super(context, R.layout.listview_item, first, second, third); 
     this.context = context; 
     this.first = first; 
     this.second = second; 
     this.third = third; 
    } 

错误：构造ArrayAdapter（上下文，INT的String []，字符串[]的String []）是不确定的

原文出处

public class ListViewAdapter extends ArrayAdapter<String> { 
    Context context; 
    String[] first; 
    String[] second; 
    String[] third; 
    LayoutInflater inflater; 

    public ListViewAdapter(Context context, String[] first, String[] second, String[] third) { 
     super(context, R.layout.listview_item, first); 
     this.context = context; 
     this.first = first; 
     this.second = second; 
     this.third = third; 
    } 

Answer 1

你应该阅读有关原则用Java编写的inheritance。你的课程正在延伸ArrayAdapter。

如果你看看它，你会发现没有为这个类定义类型为ArrayAdapter(Context, int, String[], String[], String[])的构造函数。

这就是为什么你不能这样做super(context, R.layout.listview_item, first, second, third);