多行，每个C中有6个随机数＃

Question

我试图编写一个程序，您可以输入“x”并在每行中获得具有6个随机数的“x”数量的行。我现在的代码给出了“x”数量的相同行的输出，每行有6个随机数。这是到目前为止我的代码

{ 
     Random random_generator = new Random(DateTime.Now.Millisecond); 

     int random_numbers, int_games; 

     List<int> lst_numbers = new List<int>(); 

     if (!int.TryParse(txt_input.Text, out int_games)) 
     { 
      MessageBox.Show("Please enter valid number"); 
      txt_input.Clear(); 
      txt_input.Focus(); 
     } 
     else 
      while (lst_display.Items.Count < int_games) 
      { 
       while (lst_numbers.Count < 6) 
       { 
        random_numbers = random_generator.Next(1, 45); 
        if (!lst_numbers.Contains(random_numbers)) 
        { 
         lst_numbers.Add(random_numbers); 
        } 
        else 
        { 

        } 
       } 
       lst_display.Items.Add(string.Join(",", lst_numbers)); 
      } 
    } 

Answer 1

你想执行内部循环，目前它只是执行一次，因为你是填充在该lst_numbers第一iteration.You可以与for循环，而不是取代它每次：

while (lst_display.Items.Count < int_games) 
{ 
    for(int i=0; i<6; i++) 
    { 
     random_numbers = random_generator.Next(1, 45); 
     if (!lst_numbers.Contains(random_numbers)) 
     { 
      lst_numbers.Add(random_numbers); 
     } 
    } 
    lst_display.Items.Add(string.Join(",", lst_numbers)); 
    lst_numbers.Clear(); 
} 

Answer 2

难道这不容易吗？

Public String getList(int numbersPerLine,int rows,int from,int to){ 
String list =""; 
for(int i = 1;i<= numbersPerLine;i++;){ 
    for(int j = 1;j<= rows;j++;){ 
    List += ""+((int)(Math.random()*to)+from)+","; 
    } 
    list +=\n";//for starting new line... 
} 
return list; 
}