从字典阵列中获取值bash

Question

我在学习如何bash脚本，并且我需要知道如何从字典数组中获取值。我这样做的声明：

declare -a persons 
declare -A person 
person[name]="Bob" 
person[id]=12 
persons[0]=$person 

如果我下面的正常工作：

echo ${person[name]} 
# Bob 

但是，当我试图从阵列访问值这是行不通的。我试过这些选项：

echo ${persons[0]} 
# empty result 
echo ${persons[0][name]} 
# empty result 
echo persons[0]["name"] 
# persons[0][name] 
echo ${${persons[0]}[name]} #It could have worked if this work as a return 
# Error 

我不知道还有什么更多的尝试。任何帮助，将不胜感激！

谢谢您的阅读！

猛砸版本：48年3月4日

Answer 1

多维数组的概念是不bash支持，所以

${persons[0][name]} 

将无法​​正常工作。但是，从Bash 4.0开始，bash具有关联数组，您似乎已经尝试过，这适合您的测试用例。例如，你可以这样做：

#!/bin/bash 
declare -A persons 
# now, populate the values in [id]=name format 
persons=([1]="Bob Marley" [2]="Taylor Swift" [3]="Kimbra Gotye") 
# To search for a particular name using an id pass thru the keys(here ids) of the array using the for-loop below 

# To search for name using IDS 

read -p "Enter ID to search for : " id 
re='^[0-9]+$' 
if ! [[ $id =~ $re ]] 
then 
echo "ID should be a number" 
exit 1 
fi 
for i in ${!persons[@]} # Note the ! in the beginning gives you the keys 
do 
if [ "$i" -eq "$id" ] 
then 
    echo "Name : ${persons[$i]}" 
fi 
done 
# To search for IDS using names 
read -p "Enter name to search for : " name 
for i in "${persons[@]}" # No ! here so we are iterating thru values 
do 
if [[ $i =~ $name ]] # Doing a regex match 
then 
    echo "Key : ${!persons[$i]}" # Here use the ! again to get the key corresponding to $i 
fi 
done