在ruby中删除重复的数据

Question

我想基于所有三个字段，即基于事件名称，日期和时间从我的代码中删除重复项，如果所有三个字段都匹配两个事件，则应删除一个，只显示唯一events。我写的代码仅适用于一个字段，即根据eventname删除条目。如何匹配所有三个字段。我正在使用&，但没有成功。

include Enumerable 

list = [ 
    { 
    :eventname => "music show", 
    :date => "1st august", 
    :time => "9 pm" 
    }, 
    { 
     :eventname => "dance show", 
     :date => "11st august", 
     :time => "9 pm" 
    }, 
    { 
     :eventname => "music show", 
     :date => "1st august", 
     :time => "9 pm" 
    }, 
    { 
     :eventname => "music show", 
     :date => "15st august", 
     :time => "9 pm" 
    }, 
    { 
     :eventname => "magic show", 
     :date => "12st august", 
     :time => "9 pm" 
    }, 
    { 
     :eventname => "rock show", 
     :date => "1st august", 
     :time => "9 pm" 
    } 
] 

b=list.group_by{|r| r[:eventname]}.map do |k, v| 
    v.inject({}) { |r, h| r.merge(h){ |key, o, n| o || n } } 
end 

Answer 1

使用uniq mthod的Array：

list.uniq