2011-04-12 73 views
2

我有一个hibernate实体(paygrade)与多个孩子(paysteps),我试图在应用程序中查询这些孩子。不幸的是,我只能检索查询的第一条记录。这里有休眠一对多不返回完整的结果集

public class Paygrade extends Persistent { 

    @Id 
    @Column(length = 80, updatable=false) 
    private String code; 

    @Column(length = 80, updatable=false) 
    private String name; 

    @OneToMany(mappedBy = "paygrade", fetch = FetchType.LAZY) 
    @ForeignKey(name = "none") 
    private Set<Paystep> paygradeSteps = new HashSet<Paystep>(); 

    // getters and setters 
} 


@IdClass(PaystepPK.class) 
public class Paystep { 

    @Id 
    @Column(length = 80, updatable=false) 
    protected String gradeCode; 

    @Column(length = 80, updatable=false) 
    protected String gradeName; 

    @Id 
    @Column(length = 80, updatable=false) 
    protected String scaleCode; 

    @Column(length = 80, updatable=false) 
    protected String scaleName; 

    @Column(length = 80, updatable=false) 
    protected String scalePoint; 

    @Column(updatable=false) 
    protected Long scaleValue; 

    @ManyToOne 
    @ForeignKey(name = "none") 
    @JoinColumn (name="grade_code", updatable = false, insertable = false) 
    private Paygrade paygrade; 

    // getters and setters 

} 

下面的查询是Hibernate调用getPaygradeSteps当paygrade实例()方法调用的实体:

Hibernate: 
/* load one-to-many ...Paygrade.paygradeSteps */ select 
    paygradest0_.grade_code as grade1_38_1_, 
    paygradest0_.grade_code as grade1_1_, 
    paygradest0_.scale_code as scale2_1_, 
    paygradest0_.grade_code as grade1_39_0_, 
    paygradest0_.scale_code as scale2_39_0_, 
    paygradest0_.grade_name as grade3_39_0_, 
    paygradest0_.scale_name as scale4_39_0_, 
    paygradest0_.scale_point as scale5_39_0_, 
    paygradest0_.scale_value as scale6_39_0_ 
from 
    tv_grade_point paygradest0_ 
where 
    paygradest0_.grade_code= 'Grade 9' 

查询从数据库返回9个结果,但冬眠只有永远检索第一条记录。我假设它可能与paystep的组合键(使用休眠与遗留数据库相关的危险)有关。

有谁知道为什么会出现这种行为?

回答

0

您需要在OneToMany引用中指定连接列"grade_code"并使其反转。

顺便说一句:您的问题中的SQL查询正在检索tv_grade_point,而不是Paystep。