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我有一个hibernate实体(paygrade)与多个孩子(paysteps),我试图在应用程序中查询这些孩子。不幸的是,我只能检索查询的第一条记录。这里有休眠一对多不返回完整的结果集
public class Paygrade extends Persistent {
@Id
@Column(length = 80, updatable=false)
private String code;
@Column(length = 80, updatable=false)
private String name;
@OneToMany(mappedBy = "paygrade", fetch = FetchType.LAZY)
@ForeignKey(name = "none")
private Set<Paystep> paygradeSteps = new HashSet<Paystep>();
// getters and setters
}
@IdClass(PaystepPK.class)
public class Paystep {
@Id
@Column(length = 80, updatable=false)
protected String gradeCode;
@Column(length = 80, updatable=false)
protected String gradeName;
@Id
@Column(length = 80, updatable=false)
protected String scaleCode;
@Column(length = 80, updatable=false)
protected String scaleName;
@Column(length = 80, updatable=false)
protected String scalePoint;
@Column(updatable=false)
protected Long scaleValue;
@ManyToOne
@ForeignKey(name = "none")
@JoinColumn (name="grade_code", updatable = false, insertable = false)
private Paygrade paygrade;
// getters and setters
}
下面的查询是Hibernate调用getPaygradeSteps当paygrade实例()方法调用的实体:
Hibernate:
/* load one-to-many ...Paygrade.paygradeSteps */ select
paygradest0_.grade_code as grade1_38_1_,
paygradest0_.grade_code as grade1_1_,
paygradest0_.scale_code as scale2_1_,
paygradest0_.grade_code as grade1_39_0_,
paygradest0_.scale_code as scale2_39_0_,
paygradest0_.grade_name as grade3_39_0_,
paygradest0_.scale_name as scale4_39_0_,
paygradest0_.scale_point as scale5_39_0_,
paygradest0_.scale_value as scale6_39_0_
from
tv_grade_point paygradest0_
where
paygradest0_.grade_code= 'Grade 9'
查询从数据库返回9个结果,但冬眠只有永远检索第一条记录。我假设它可能与paystep的组合键(使用休眠与遗留数据库相关的危险)有关。
有谁知道为什么会出现这种行为?