春错误404试图访问myController的

Question

我新的春天。我正在尝试将Spring集成到Web应用程序的一部分中。 它有像URL的工作：

http://localhost:9080/myfolder/myspring 

我web.xml中包括：

<context-param> 
    <param-name>contextConfigLocation</param-name> 
    <param-value>  
    /WEB-INF/config/myspring-context.xml 
    </param-value> 
</context-param> 


    <servlet> 
     <servlet-name>dispatcher</servlet-name> 
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
     <init-param> 
    <param-name>contextConfigLocation</param-name> 
    <param-value> 
     /WEB-INF/config/applicationContext.xml 
    </param-value> 
    </init-param> 
     <load-on-startup>1</load-on-startup> 
    </servlet>  

    <servlet-mapping> 
     <servlet-name>dispatcher</servlet-name> 
     <url-pattern>/springviews</url-pattern> 
    </servlet-mapping> 

的applicationContext.xml：

<?xml version="1.0" encoding="UTF-8"?> 

    <beans xmlns="http://www.springframework.org/schema/beans" 
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
      xmlns:jee="http://www.springframework.org/schema/jee" 
      xmlns:context="http://www.springframework.org/schema/context" 
      xmlns:tx="http://www.springframework.org/schema/tx" 
      xmlns:aop="http://www.springframework.org/schema/aop" 
      xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd 
        http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd 
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd 
        http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd 
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd"> 

     <!-- registers all of Spring's standard post-processors for annotation-based configuration --> 
     <context:annotation-config /> 

     <tx:annotation-driven/> 
     <tx:jta-transaction-manager/> 

     <bean id="properties" class="springcop.pojo.TestObject"> 

     </bean> 

    </beans> 

我myspring上下文。 xml是：

<?xml version="1.0" encoding="UTF-8"?> 

<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd 
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> 

    <!-- Scans within the base package of the application for @Components to configure as beans --> 
    <!-- @Controller, @Service, @Configuration, etc. --> 
<context:component-scan base-package="springcop"/> 

<!-- Configures the @Controller programming model --> 
<mvc:annotation-driven/> 

<!-- Resolve logical view names to .jsp resources in the /WEB-INF/views directory --> 
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
    <property name="prefix" value="/WEB-INF/springviews/" /> 
    <property name="suffix" value=".jsp" /> 
</bean> 



</beans> 

这里是myController的

package springcop; 

import java.util.Map; 

import org.springframework.stereotype.Controller; 
import org.springframework.web.bind.annotation.RequestMapping; 
import org.springframework.beans.factory.annotation.Value; 

import org.springframework.ui.ModelMap; 
import org.springframework.web.bind.annotation.RequestMethod; 

@Controller 
public class MyController { 


    public MyController() { 
     System.out.println("--->GestioneController"); 

    } 


    @RequestMapping(value = "/test", method = RequestMethod.GET) 
     public String test() { 
     System.out.println("--->test"); 
     return "test"; 
    } 

} 

向上是没有错误runniong。春天似乎工作，因为我已经在我的日志“---> GestioneController这是在我的控制器的构造函数。

无论如何，当我在浏览器中打开

http://localhost:9080/myfolder/myspring/test 

执行测试打印出来在方法myController的，我得到404错误。

什么是我应该做的，使其工作？ 感谢。

Answer 1

假设你的web应用的名称是myfolder如问题上市，网址是...

http://localhost:9080/myfolder/springviews/test 

问题是你有调度servlet映射到springviews。你需要在web.xml中映射如下调度的servlet ...

<servlet-mapping> 
    <servlet-name>dispatcher</servlet-name> 
    <url-pattern>/<url-pattern> 
</servlet-mapping> 

编辑：此外，你已经把你的Spring配置中的context-param，但你没有添加监听器接它起来。添加以下到您的web.xml ....

<listener> 
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
</listener>