2010-06-16 100 views
1

我有一个Ajax函数,它将从服务器检索一些RSS提要脚本。javascript作为响应文本

$("#divId").html(responsetext); 

我想执行的响应里面的脚本:我用把这个responseText的在一个div。目前,RSS源并未在div中显示。有没有办法做到这一点?谢谢..

responsetext 
------------- - 

<div class="last-updated" style="display: block" id="p-lastUpdated">Last Updated:16 Jun 2010 10:32 AM</div> 

<div id="digg-widget-1276598296115"> 

<a href="http://digg.com/search?s=timesofindia.indiatimes.com">See more timesofindia.indiatimes.com stories.</a> 

</div> 

<script type="text/javascript"> 

(function() { var s, s1, diggWidget = {id: "digg-widget-1276598296115", layout: 1, colors: {hdrBg: "#1b5790", hdrTxt: "#b3daff", tabBg: "#4684be", tabTxt: "#b3daff", tabOnTxt: "#d41717", bdyBg: "#fff", stryBrdr: "#ddd", lnk: "#105cb6", descTxt: "#999999", subHd: "#999999"}, title: "RSS Times of india", width: 480,height: 300, requests: [{t: "timesofindia.indiatimes.com", p: {count: "10", sort: "promote_date-desc", method: "story.getPopular", domain: "timesofindia.indiatimes.com"}}], hide: {footer: true, header: true}, target: "_blank", descriptions: "show", rounded: true}; if (window.DiggWidget) { if (typeof DiggWidget == 'function') { new DiggWidget(diggWidget); } else { DiggWidget.push(diggWidget); } } else { DiggWidget = [diggWidget]; s = document.createElement('SCRIPT'); s.type = 'text/javascript'; s.async = true; s.src = 'http://widgets.digg.com/widgets.js'; s1 = document.getElementsByTagName('SCRIPT')[0]; s1.parentNode.insertBefore(s, s1); } })(); 

</script> 
+1

我的回答是你在不同的域抓取RSS源? – 2010-06-16 10:02:52

+0

嗨,尼克,它来自同一个域 – Aneesh 2010-06-16 10:27:41

+0

你必须非常确定响应中的脚本不包含恶意代码。 – 2010-06-16 11:39:10

回答

0

How To Call Javascript In Ajax Response? IE: Close a form div upon success

// response is the data returned from the server 
var response = "html\<script type=\"text/javascript\">alert(\"foo\");<\/script>html"; 
var reScript = /\<script.*?>(.*)<\/script>/mg; 
response = response.replace(reScript, function(m,m1) { 
    eval(m1); //will run alert("foo"); 
    return ""; 
}); 
alert(response); // will alert "htmlhtml" 
+0

嗨肖恩,非常感谢你的答案。但这不是在我的情况。我已经更新了问题的回应文本 – Aneesh 2010-06-17 09:37:26

+0

你是什么意思的'不工作'? – 2010-06-17 22:29:57

0

是响应混合HTML和JavaScript或只是纯粹的JavaScript?

如果它是纯粹的JavaScript,您可以随时使用执行发送代码的eval("alert('Test');")函数。

+0

它是混合的HTML和JavaScript ... :( – Aneesh 2010-06-16 10:28:14