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我有一个简单的脚本，目前发送电子邮件给3人。cron作业不会触发工作的PHP脚本，生成错误
如果我直接转到url，脚本正常工作（它发送电子邮件）。
但是，如果我把它作为的cPanel cron作业，我得到如下通知我的cron电子邮件时cron作业火灾：
/home/ultranet/public_html/newsletter/blast_script.php: line 1: ?php: No such file or directory
/home/ultranet/public_html/newsletter/blast_script.php: line 2: /*: No such file or directory
/home/ultranet/public_html/newsletter/blast_script.php: line 3: Script: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 4: January: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 5: Please: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 6: ----------------------------------------------------------------------: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 7: include_once: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 8: syntax error near unexpected token `('
/home/ultranet/public_html/newsletter/blast_script.php: line 8: `$sql = mysql_query("SELECT * FROM newsletter WHERE received='1' LIMIT 20");'
和脚本是：
<?php
/* -------------------------------------------------------------------
Script written by Adam Khoury @ www.developphp.com
January 1, 2010
Please retain this credit when displaying this code online
---------------------------------------------------------------------- */
include_once "connect_to_mysql.php";
$sql = mysql_query("SELECT * FROM newsletter WHERE received='1' LIMIT 20");
$numRows = mysql_num_rows($sql); // Added for "End Campaign Check" at the bottom of this file(not shown on the video)
$mail_body = '';
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$email = $row["email"];
$name = $row["name"];
$mail_body = '<html>
<body style="background-color:#CCC; color:#000; font-family: Arial, Helvetica, sans-serif; line-height:1.8em;">
<h3><a href="http://www.developphp.com"><img src="http://www.yoursite.com/images/logo.png" alt="DevelopPHP" width="216" height="36" border="0"></a> Newsletter
</h3>
<p>Hello ' . $name . ',</p>
<p>You can make this out to be just like most any web page or design format you require using HTML and CSS.</p>
<p>~Adam @ DevelopPHP</p>
<hr>
<p>To opt out of receiving this newsletter, <a href="http://www.developphp.com/Tests/newsletter/optout.php?e=' . $email . '">click here</a> and we will remove you from the listing immediately.</p>
</body>
</html>';
$subject = "Develop PHP Newsletter";
$headers = "From:[email protected]\r\n";
$headers .= "Content-type: text/html\r\n";
$to = "$email";
$mail_result = mail($to, $subject, $mail_body, $headers);
if ($mail_result) {
// mysql_query("UPDATE newsletter SET received='1' WHERE email='$email' LIMIT 1");
} else {
// this else statement can be used to write into an error log if the mail function fails
// It can also be removed if you do not need error logging
}
}
// This section is script I discussed adding to this file on video
// This section is for sending the site owner a message informing them that
// all people in the database have been sent the newsletter for the current campaign
if ($numRows == 0) { // $numRows is set on line 4 using the existing query
$subj = "Newsletter Campaign Has Ended";
$body = "The current newsletter campaign has ended. All have been sent the newsletter.";
$hdr = "From:[email protected]\r\n";
$hdr .= "Content-type: text/html\r\n";
mail("yourEmailAddressHere", $subj, $body, $hdr);
}
// End Check Section
?>
它为什么会产生错误，因为直接在url中调用脚本时脚本正常工作？
我问我的主人，但他们不知道问题是什么。
听起来像PHP可执行文件无法找到..在常规的crontab中，例如，您会添加PATH =/bin：/ usr/bin：/ usr/local/bin。 – Oli 2015-02-10 08:42:45
查看我的解决方案 – 2015-02-10 08:51:18
我的主持人告诉我要从字面上加上以下内容：/home/ultranet/public_html/newsletter/blast_script.php – 2015-02-10 09:01:47