我尝试只插入两个整数变量到我的sqlite数据库。我创建了一个名为ups.sqlite的数据库,它有一个表(upssTable),表中有两列。但是当我打开/ Users/ds/Library/Application Support/iPhone Simulator/5.0/Applications/FCB4B455-4B7F-4C47-81B6-AC4121874596/SqliteDeneme.app/ups.sqlite时,ups.sqlite中没有数据。我的代码在这里:Sqlite数据库插入目标C语句
- (IBAction)buttonClick:(id)sender {
NSFileManager *fileManager = [NSFileManager defaultManager];
NSError *error;
NSString *dbPath = [self getDBPath];
BOOL success = [fileManager fileExistsAtPath:dbPath];
if(!success) {
NSString *defaultDBPath = [[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"ups.sqlite"];
success = [fileManager copyItemAtPath:defaultDBPath toPath:dbPath error:&error];
if (!success)
NSAssert1(0, @"Failed to create writable database file with message '%@'.", [error localizedDescription]);
}
NSLog(@"database path %@",dbPath);
if(!(sqlite3_open([dbPath UTF8String], &cruddb) == SQLITE_OK))
{
NSLog(@"An error has occured.");
}
if(sqlite3_open([dbPath UTF8String], &cruddb) ==SQLITE_OK){
NSString * str1 [email protected]"1";
NSString * str2 [email protected]"1";
const char *sql = "INSERT INTO upssTable (column1, column2) VALUES (?,?)";
NSInteger result = sqlite3_prepare_v2(cruddb,sql, -1, &stmt, NULL);
NSLog(@"upss %s\n", sqlite3_errmsg(cruddb));
if(result == SQLITE_OK)
{
sqlite3_bind_int(stmt, 1, [str1 integerValue]);
sqlite3_bind_int(stmt, 2, [str2 integerValue]);
}
else
{
NSAssert1(0, @"Error . '%s'", sqlite3_errmsg(cruddb));
}
sqlite3_reset(stmt);
sqlite3_finalize(stmt);
sqlite3_close(cruddb);
}
}
- (NSString *) getDBPath {
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory , NSUserDomainMask, YES);
NSString *documentsDir = [paths objectAtIndex:0];
return [documentsDir stringByAppendingPathComponent:@"ups.sqlite"];
}
我该如何解决这个问题?请帮帮我。感谢您的回复。