Java的数量需要在回答

Question

因此，这里少一个是我的代码：

package e7; 
import java.util.Scanner; 
public class Q1 { 

    public static void main(String[] args) 
    { 
     double[] scores = new double[10]; 
     double sum = 0.0D; 
     int count = 0; 

     Scanner sc = new Scanner(System.in); 

     do { 
      System.out.print("Enter a new score (-1 to end): "); 
      scores[count] = sc.nextDouble(); 

      if (scores[count] >= 0.0D) 
       sum += scores[count]; 

     } 

     while (scores[(count++)] >= 0.0D); 

     System.out.println("The total number of scores is: " + count); 

     double average = sum/(count - 1); 
     int numOfAbove = 0; 
     int numOfBelow = 0; 

     for (int i = 0; i < count - 1; i++) { 
      if (scores[i] >= average) 
       numOfAbove++; 
      else 
       numOfBelow++; 
     } 

     System.out.printf("Average is " + "%.2f\n",average); 
     System.out.println("Number of scores above or equal to the average " + numOfAbove); 
     System.out.println("Number of scores below the average " + numOfBelow); 

    } 

    } 

如何让它显示计算的分数是否正确？如果我输入2个数字，然后做-1来结束它不断说3分数。应该只有两个。我该如何解决？由于

Answer 1

System.out.println("The total number of scores is: " + count); 

你可能想：

System.out.println("The total number of scores is: " + (count - 1)); 

Answer 2

你也可以从一个做改变你的循环，而while循环如下，

while (true) { 
    System.out.print("Enter a new score (-1 to end): "); 
    double tempDouble = sc.nextDouble(); 

    if (tempDouble >= 0.0D) 
    scores[count] = tempDouble; 
    sum += scores[count]; 
    count++; 
    else 
    break; 
} 

这样一来，就好像你的双输入是不正确的，它会在用户输入-1时跳出while循环。你可能需要为你的用例调整一下。