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由于react-router并未向链接或li添加活动类,因此我希望将活动链接保留在我的菜单状态中。当我登录this.state.activeLink时,我得到了正确的值,但由于某种原因,类'activeLink'没有被添加到li中。为什么是这样? isActive()在我登录时正确返回true或false,但仍然不会将该类添加到li中。这里发生了什么?反应路由器跟踪活动链接
import React, { Component } from 'react';
import { Link } from 'react-router-dom';
import logo from '../images/logo.png';
export default class Navbar extends Component {
constructor(props){
super(props);
this.state = { activeLink : '' };
this.setActive = this.setActive.bind(this);
}
setActive(event){
this.setState({ activeLink: event.target.id });
}
isActive(link){
console.log('isActive:', link == this.state.activeLink);
link == this.state.activeLink ? 'activeLink' : '';
}
render(){
return (
<div className="header">
<div className="row">
<div className="header-left">
<div className="logo">
<img src={logo} alt=""/>
</div>
<div className="header-title">Physical Twist</div>
<div className="menu">
<ul className="nav">
<li className={this.isActive('home')}><Link to="/" id="home" onClick={this.setActive}>Home</Link></li>
<li className={this.isActive('store')}><Link to="/store" id="store" onClick={this.setActive}>Store</Link></li>
<li className={this.isActive('catalogue')}> <Link to="#" id="catalogue" onClick={this.setActive}>Catalogue</Link></li>
<li className={this.isActive('contact')} ><Link to="#" id="contact" onClick={this.setActive}>Contact</Link></li>
</ul>
</div>
</div>
</div>
</div>
);
};
}
Doooooooh。一直在做太多的Ruby:P感谢队友! – stoerebink