嗨大家即时通讯使用winapi和我想做一个在三维正方形即时通讯定义的要点,以使他们与功能和我一直在尝试3个功能,但我不能让他们工作,我得到同样的错误在他们3。 <不能将struct **转换为const POINT *作为参数?
的错误说
In member function `void Cube::Show(void)':|
cannot convert `const Cube::Show()::POINT3D**' to `const POINT*'
for argument `2' to `BOOL Polygon(HDC__*, const POINT*, int)'|
错误使用或者多边形功能或polybezier或折线指向时,即时通讯
PLZ任何帮助将真正理解
void Cube::Show(void)
{
typedef struct point3d
{
double x;
double y;
double z;
} POINT3D;
POINT3D Face1[] = {
{ 20.0,-20.0,-20.0},
{-20.0,-20.0,-20.0},
{-20.0, 20.0,-20.0},
{ 20.0, 20.0,-20.0}
};
POINT3D Face2[] = {
{-20.0,-20.0,-20.0},
{-20.0,-20.0, 20.0},
{-20.0, 20.0, 20.0},
{-20.0, 20.0,-20.0}
};
POINT3D Face3[] = {
{ 20.0, 20.0, 20.0},
{-20.0, 20.0, 20.0},
{-20.0,-20.0, 20.0},
{ 20.0,-20.0, 20.0}
};
POINT3D Face4[] = {
{ 20.0,-20.0, 20.0},
{ 20.0,-20.0,-20.0},
{ 20.0, 20.0,-20.0},
{ 20.0, 20.0, 20.0}
};
POINT3D Face5[] = {
{ 20.0,-20.0, 20.0},
{-20.0,-20.0, 20.0},
{-20.0,-20.0,-20.0},
{ 20.0,-20.0,-20.0}
};
POINT3D Face6[] = {
{ 20.0, 20.0,-20.0},
{-20.0, 20.0,-20.0},
{-20.0, 20.0, 20.0},
{ 20.0, 20.0, 20.0}
};
POINT3D *Faces[] = {Face1,Face2,Face3,Face4,Face5,Face6};
Rectangle(this->_hdc,this->DrawArea.left,this->DrawArea.top,this->DrawArea.right,this->DrawArea.bottom);
Polygon(_hdc,Faces,6);
/*BeginPath(_hdc);
PolyBezier(Faces,6);
EndPath(_hdc);*/
//Polyline(_hdc,Faces,6);
}
我们需要比这更多的信息。什么是_hdc?以及Rectangle()和Polygon()如何定义?另外,我非常确定'POINT3D * Faces [] = {Face1,Face2,Face3,Face4,Face5,Face6}'是无效的语法。你为什么使用一个结构来代替你的点而不是类? – Falmarri 2010-08-30 03:29:05
呵呵,我认为结构只是更容易为这种情况下,但我也可以使用该和多边形和矩形是winapi函数已经宣布我没有让他们:S和HDC以及它的HDC的WINAPI – Makenshi 2010-08-30 03:31:26
以及我可以只使用窗户。 h库,所以我不知道是否回答你的问题,所以即时通讯尝试制作3d-2d的东西lol – Makenshi 2010-08-30 03:35:24