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经典表:用户,auth_item(用于角色/权限),auth_assignment结对多对多用户< - >角色。yii2 GridView多对多结点表显示
我遵循(或试图跟随)文档和其他人的问题。我想出了以下(我有我的课对我的ActiveRecord测试的“AR”前缀):
在“用户”模式(型号/ Aruser.php):
public function getRoles() {
return $this->hasMany(ArauthItem::className(), ['name' => 'item_name'])
->viaTable('auth_assignment', ['user_id' => 'id']);
}
在“角色“模型,又名auth_item表型号(型号/ ArauthItem.php):
public function getUsers() {
return $this->hasMany(Aruser::className(), ['id' => 'user_id'])
->viaTable('auth_assignment', ['item_name' => 'name']);
}
在 ”用户搜索“ 模型(模型/ ArusersSearch.php):
class AruserSearch extends Aruser{
public $roles;
public function rules()
{
return [
[['id', 'status', 'created_at', 'updated_at'], 'integer'],
[['username', 'auth_key', 'password_hash', 'password_reset_token', 'email','roles'], 'safe'],
];
}
public function search($params)
{
$query = Aruser::find();
$query->joinWith(['roles']);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
/* ... some skipped code, the usual ... */
$query->andFilterWhere(['like', 'username', $this->username])
->andFilterWhere(['like', 'auth_key', $this->auth_key])
->andFilterWhere(['like', 'password_hash', $this->password_hash])
->andFilterWhere(['like', 'password_reset_token', $this->password_reset_token])
->andFilterWhere(['like', 'email', $this->email])
->andFilterWhere(['like', 'auth_item.name', $this->roles]);
return $dataProvider;
}
}
最后,在视图文件:
GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'id',
'username',
'auth_key',
'password_hash',
'password_reset_token',
'roles.name',
/*
[
'attribute' => 'roles',
// this is an anonymous function built by me to retrieve correct concatanated related m to n values, but is it the proper and correct way?
'value' => function ($model) {
$multiple_res = '';
foreach($model->roles as $role){
$multiple_res .= ($multiple_res?',':'').$role->name;
}
return $multiple_res;
},
],
*/
['class' => 'yii\grid\ActionColumn'],
],
]);
我不能让角色栏,显示什么,但“(未设置)”,除非我用的是匿名函数,你可以看到上面的评论。什么是Yii2> GridView在一列中显示多对多连接的方式?我究竟做错了什么?
非常感谢!
谢谢ttdijkstra,只是一个小评:破灭在这里并不适用,$模型 - >角色是采取阵列 – dev299
点的数组。我多么粗心。 – ttdijkstra
谢谢ttdijkstra,这很有帮助。 – RezaGM