如何通过JSON数组与Servlet

Question

[DUPICATE]

这我POST JSON代码

var data_create = JSON.stringify($("#form_create_delegate").serializeArray()); 

     alert("isi data_create" + data_create); 

//  console.log(data_create) 
     $.ajax({ 
      type: "POST", 
      url: "formCreateDelegationServlet", 
      dataType: "json", 
      data:data:{JSONFile:data_create}, 
      success: function (response) { } 


     }); 

这是我的结果JSON

JSONFile:[{"name":"id_form_delegate","value":"1"},{"name":"merchant","value":"AMBHARA HOTEL TERBAIK"},{"name":"citty","value":"JAKARTA PUSAT"},{"name":"addrs","value":"JL. DIPONEGORO NO. 1J"},{"name":"province_merchant","value":"DKI JAKARTA"},{"name":"mid_merchant[]","value":"1"},{"name":"tid_merchant[]","value":"1"},{"name":"mid_merchant[]","value":"2"},{"name":"tid_merchant[]","value":"2"}] 

如何删除属性 “名” 和“价值”从我的JsonArray

我想制作一个这样的格式

[{"merchant":"AMBHARA HOTEL TERBAIK","citty":"JAKARTA PUSAT"}] 

这是我的servlet代码

JSONArray jsonArray = (JSONArray) net.sf.json.JSONSerializer.toJSON(request.getParameter("JSONFile")); 

      merchant = jsonObject.getString("merchant"); 
      city = jsonObject.getString("city"); 
      addrs = jsonObject.getString("addrs"); 
      province_merchant = jsonObject.getString("province_merchant"); 
      tid = jsonObject.getString("tid_merchant"); 
      mid = jsonObject.getString("tid_merchant"); 
//    
      System.out.println("nama_merchant: " + nama_merchant); 
      System.out.println("kota_merchant: " + kota_merchant); 
      System.out.println("alamat_merchant: " + alamat_merchant); 
      System.out.println("province_merchant: " + province_merchant); 
      System.out.println("mid: " + mid); 
      System.out.println("tid: " + tid); 

但它不如果你想摆脱键，只是保留值数组，你可以使用阵列工作

Answer 1

。像这样的地图

var input=[{"name":"id_form_delegate","value":"1"},{"name":"merchant","value":"AMBHARA HOTEL TERBAIK"},{"name":"citty","value":"JAKARTA PUSAT"},{"name":"addrs","value":"JL. DIPONEGORO NO. 1J"},{"name":"province_merchant","value":"DKI JAKARTA"},{"name":"mid_merchant[]","value":"1"},{"name":"tid_merchant[]","value":"1"},{"name":"mid_merchant[]","value":"2"},{"name":"tid_merchant[]","value":"2"}] 
 

 
var result = input.map(function (obj) {return [obj.name, obj.value]}) 
 

 
console.log(JSON.stringify(result))

您可以使其成为动态的，以便它可以使用任何属性，而不仅仅是“名称”和“值”，使用Object.keys（MSIE pre 9中不支持）。但要小心，你失去了对输出值的顺序的控制。

input=[{"name":"id_form_delegate","value":"1"},{"name":"merchant","value":"AMBHARA HOTEL TERBAIK"},{"name":"citty","value":"JAKARTA PUSAT"},{"name":"addrs","value":"JL. DIPONEGORO NO. 1J"},{"name":"province_merchant","value":"DKI JAKARTA"},{"name":"mid_merchant[]","value":"1"},{"name":"tid_merchant[]","value":"1"},{"name":"mid_merchant[]","value":"2"},{"name":"tid_merchant[]","value":"2"}] 
 

 
result = input.map(function (obj) { 
 
    return Object.keys(obj).map(function (key) {return obj[key]}) 
 
}) 
 

 
console.log(JSON.stringify(result))