我需要采取一列中的前半部分单词,并存储在另一列。 我可以假设有偶数的单词。 我用它做了一个游标和一个函数,我发现它需要一个字符串并使用分隔符将它解析到一个表中。试图摆脱光标更新
drop table #test
create table #test (id int identity, my_name varchar(128), cleaned_name varchar(128))
insert into #test (my_name) VALUES ('abcd efgh abcd1 efgh1')
insert into #test (my_name) VALUES ('name1 name2 name1a name2a')
insert into #test (my_name) VALUES ('one two one* two*')
select *
from #test
DECLARE @HalfName varchar(100)
DECLARE @i varchar(100)
set @i = 1
while @i <= (select count(*) from #test)
begin
SELECT @HalfName = COALESCE(@HalfName + ' ', '') + aa.WORD
FROM (select top (select count(*)/2 from dm_generic.dbo.GETALLWORDS((select [my_name]
from #test
where id = @i), ' ')) *
from dm_generic.dbo.GETALLWORDS(
(select [my_name]
from #test
where id = @i), ' ')
) aa
update #test
set cleaned_name = @HalfName
where id = @i
set @i = @i + 1
set @HalfName = ''
end
select *
from #test
我试图做到这一点无光标:
UPDATE bb
SET cleaned_name =
(SELECT COALESCE (bb.cleaned_name + ' ', '') + aa.WORD
FROM (SELECT TOP (SELECT count (*)/2
FROM dm_generic.dbo.GETALLWORDS (
(SELECT [my_name]
FROM #test a
WHERE a.id = bb.id),
' '))
*
FROM dm_generic.dbo.GETALLWORDS ((SELECT [my_name]
FROM #test b
WHERE b.id = bb.id),
' ')) aa)
FROM #test bb
什么,我得到的是:
Msg 512, Level 16, State 1, Line 1
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.
The statement has been terminated.
任何帮助将不胜感激。
感谢所有响应,我终于用this solution通过@BradC酿造我自己的,那就是:
update updated
set cleaned_name = (
SELECT Clean
FROM #test AS extern
CROSS APPLY
(
select TOP (SELECT count (*)/2
FROM dm_generic.dbo.GETALLWORDS (
(SELECT [my_name]
FROM #test a
WHERE a.id = extern.id), ' '))
WORD + ' '
FROM dm_generic.dbo.GETALLWORDS (
(SELECT [my_name]
FROM #test a
WHERE a.id = extern.id),
' ')
FOR XML PATH('')
) pre_trimmed (Clean)
where extern.id = updated.id)
from #test updated
@NikolaMarkovinović解决方案的伟大工程,以及。
我收到“Msg 174,Level 15,State 1,Line 3 stuff函数需要4个参数。” 。价值是什么以及它在同一行中的价值是什么? – bodman 2012-04-10 12:15:07
@bodman希望我已经纠正了我的答案。 – 2012-04-10 12:23:45
是@NikolaMarkovinović现在可以工作,但'+ aa.my_name实际上应该是''+ aa.WORD,它是从GETALLWORDS返回的列的名称。我仍然试图弄清楚这是什么:.value('(./ text())[1]','VARCHAR(MAX)') – bodman 2012-04-11 07:52:25