Laravel附近的商店

我试图在Laravel 5.1中获得neraby商店我有地理编码解析器，caluclate coorinate。但是，我有与haversine公式问题。基本上我需要从表Aziende（商店）给出一个lat，long e类别通过低谷url，拿取附近的商店。Laravel附近的商店

我尝试使用此代码：

$dove = Input::get('dove'); 
    $categoria_id = Input::get('id_categoria'); 
    // 4: check if any matches found in the database table 
    if (!empty($dove)) { 
     $response = \GoogleMaps::load('geocoding')->setParamByKey ('address', $dove)->get(); 
     $response = json_decode($response, true); 
     $latitude = $response['results'][0]['geometry']['location']['lat']; 
     $longitude = $response['results'][0]['geometry']['location']['lng']; 
     $radius = '5'; 
     $aziende = DB::table('aziende') 
      ->select(
       ('lat * acos(cos(radians(50)) * cos(radians(lat)) * cos(radians(lng) - radians(-122)) 
         + sin(radians(37)) * sin(radians(lat))) as distance'))->get(); 




    } else { 
    $aziende = DB::table("aziende")->where('categoria', $categoria_id)->get(); 
} 
?>

来源

2016-11-26 rubenSousa

你使用什么数据库/版本？如果你使用MySQL，你有ST_Distance ... v5.7有ST_Distance_Sphere https://dev.mysql.com/doc/refman/5.7/en/spatial-convenience-functions.html – jcorry

下面应该为你工作，以实现在一个SQL查询haversine公式。我的答案是假设你有一个模型设置与数据库表“aziende”相对应。

$lat = floatval($response['results'][0]['geometry']['location']['lat']); 
$lng = floatval($response['results'][0]['geometry']['location']['lng']); 
$radius = 5; 
$distance = DB::raw("*, (6371 * acos(cos(radians($lat)) * cos(radians(lat)) * cos(radians(lng) - radians($lng)) + sin(radians($lat)) * sin(radians(lat)))) AS distance"); 
$aziende = Aziende::select($distance)->orderBy('distance')->where('distance', '<=', $radius)->get();

来源

2016-11-30 19:58:02 MMMTroy

Laravel附近的商店

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