如何从mongo数据库聚合结果中删除waitedMS并确定？

Question

我正在mongodb php应用程序中执行聚合命令，如下面的代码行。

<?php 

$query = array('$or' => array(
    array('employeeList'=>array('$exists' => false)), 
    array('employeeList'=>array('$eq' => null)), 
    array('employeeList'=>array('$eq' => ",")), 
    array('employeeList'=>array('$eq' => "")) 
)); 

$pipeline = array(
    array(
     '$match' => $query 
    ), 
    array(
     '$lookup' => array(
      'from' => 'userTbl', 
      'localField' => 'user_id', 
      'foreignField' => 'uid', 
      'as' => 'userdetails' 
     ) 
    ), 
); 

$output = $this->db->broadcastTbl->aggregate($pipeline); 
$result =array(); 
array_push($result, $output); 

现在的输出显示为

[{"waitedMS":0,"result":[{"_id":{"$id":"58d7a6561d78597411000029"},"broadcast_id":35,"studentList":"","employeeList":"999","mailTitle":"hello","broadcastMessage":"how","emailSent":"0","userdetails":[]},{"_id":.... 
... 
"ok":1}] 

我想删除 “waitedMS”：0。 “结果”：和“ok”：1来自json。输出应该像

[{"_id":{"$id":"58d7a6561d78597411000029"},"broadcast_id":35,"studentList":"","employeeList":"999","mailTitle":"hello","broadcastMessage":"how","emailSent":"0","userdetails":[]}, ... 
] 

请帮助我！

Answer 1

您只需访问“结果”项即可。不要将它推到另一个阵列上。

<?php 

$query = array('$or' => array(
    array('employeeList'=>array('$exists' => false)), 
    array('employeeList'=>array('$eq' => null)), 
    array('employeeList'=>array('$eq' => ",")), 
    array('employeeList'=>array('$eq' => "")) 
)); 

$pipeline = array(
    array(
     '$match' => $query 
    ), 
    array(
     '$lookup' => array(
      'from' => 'userTbl', 
      'localField' => 'user_id', 
      'foreignField' => 'uid', 
      'as' => 'userdetails' 
     ) 
    ), 
); 

$output = $this->db->broadcastTbl->aggregate($pipeline); 

$result = $output["result"];