0
我已经写了一个代码,它汇总了数组的元素并使用多线程打印它。但不是使用全局值,我想使用本地值并将其返回。但是,当我使用返回线程死亡。关于如何做的任何想法?如何从python中的线程返回值?
import threading
import time
total = 0
class myThread(threading.Thread):
def __init__(self,threadId,name,starts,ends):
threading.Thread.__init__(self)
self.threadId = threadId
self.name = name
self.starts = starts
self.ends = ends
def run(self):
print "strating " + self.name
threadLock.acquire()
calc_sum(self.starts,self.ends)
threadLock.release()
def calc_sum(start,end):
global total
for i in xrange(start,end):
total += arr[i]
threadLock = threading.Lock()
threads = []
arr = [1,2,3,4,5,6,7,8,9,10]
thread1 = myThread(1,'t1',0,5)
thread2 = myThread(2,'t2',5,10)
thread1.start()
thread2.start()
threads.append(thread1)
threads.append(thread2)
for t in threads:
t.join()
print total
如何以t.total的形式访问这样的线程。你能更清楚地解释我吗? –
线程是一个列表,并通过做 '为t在线程' 你采取一个线程。然后你打电话给你的attribut总数。实际上,不是将你的总额存入全球总额中,而是存入self.total。 – fjcf1