如何从Django的request.FILES中获取文件名?如何从request.FILES获取文件名?
def upload(request):
if request.method == 'POST':
form = UploadForm(request.POST, request.FILES)
if form.is_valid():
upload = Upload()
upload.timestamp = datetime.datetime.now()
save_instance(form, upload)
我试图用这个,但它没有工作:
if 'filename' in request.FILES:
filename = request.FILES['filename']
它给了我:期望一个缩进块。我混淆:( – Pol 2010-06-24 16:39:43
好的!我怎样才能检查变量名?但是我需要打印它如何打印里面的内容? – Pol 2010-06-24 17:05:47
这是我工作的:request.FILES ['file']。name – 2015-05-13 19:58:44