修改递归函数的外部列表在Python

Question

有一个多维的清单，不清晰的结构：

a=[[['123', '456'], ['789', '1011']], [['1213', '1415']], [['1617', '1819']]] 

而且还有一个递归函数，其操作列表：

def get_The_Group_And_Rewrite_It(workingList): 
    if isinstance(workingList[0],str): 
     doSomething(workingList) 
    else: 
     for i in workingList: 
      get_The_Group_And_Rewrite_It(i) 

通过时间get_The_Group_And_Rewrite_It()应该得到一个列表，例如，['123','456']，一旦得到它，doSomething函数应该用整个列表中的['abc']来重写它。

与format[str,str,...]的其他列表相同。最后，我应该得到的东西像

a=[[['abc'], ['abc']], [['abc']], [['abc']]] 

我看到它会在C++中很容易，使用*links，但如何做到这一点在Python？

Answer 1

对于这种情况，你可以用切片赋值：

>>> a = [[['123', '456']]] 
>>> x = a[0][0] 
>>> x[:] = ['abc'] 
>>> a 
[[['abc']]] 

---

>>> def f(workingList): 
...  if isinstance(workingList[0],str): 
...   workingList[:] = ['abc'] 
...  else: 
...   for i in workingList: 
...    f(i) 
... 
>>> a=[[['123', '456'], ['789', '1011']], [['1213', '1415']], [['1617', '1819']]] 
>>> f(a) 
>>> a 
[[['abc'], ['abc']], [['abc']], [['abc']]]