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我试图在Rust里面玩多线程,我碰到过一些我认为很平凡的东西。下面的代码片段:为什么我不能尝试! Mutex.lock?
use std::thread;
use std::sync::{Arc, Mutex};
fn main() {
let vec: Vec<i32> = vec!(1, 2, 3);
let shared = Arc::new(Mutex::new(vec));
let clone = shared.clone();
let join_handle = thread::spawn(move || {
let mut data = clone.lock().unwrap();
data.push(5);
});
join_handle.join().unwrap();
let clone = shared.clone();
let vec = try!(clone.lock());
println!("{:?}", *vec);
}
所以,我的问题是上线let vec = try!(clone.lock())
。这会导致以下编译器错误:
error: mismatched types [E0308]
return $ crate :: result :: Result :: Err (
^
note: in this expansion of try! (defined in <std macros>)
help: run `rustc --explain E0308` to see a detailed explanation
note: expected type `()`
note: found type `std::result::Result<_, _>`
对我而言,这并没有多大意义。 clone.lock()
返回TryLockResult<MutexGuard<T>>
,其实质上转换为Result<MutexGuard<T>, PoisonedError<MutexGuard<T>>
,这意味着try!(clone.lock())
应解析为throw或MutexGuard<T>
。
我从根本上误解了一些东西吗?