JSon请求出错; POST 406（Not Acceptable）

Question

不断收到上面的错误，即使我已经搜索过此网站并尝试了所有内容。真的很感谢一些帮助。问题出在AddUser页面上的Jquery/JSON请求。我已经加入既杰克逊jar文件（核心和映射）。它被部署在Tomcat 7.

这是配置文件：

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xsi:schemaLocation=" 
     http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd 
     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd 
     http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd"> 

    <!-- Application Message Bundle --> 
    <bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource"> 
     <property name="basename" value="/WEB-INF/messages" /> 
     <property name="cacheSeconds" value="3000" /> 
    </bean> 

    <!-- Scans the classpath of this application for @Components to deploy as beans --> 
    <context:component-scan base-package="ajaxjqjsonbowling" /> 

    <!-- Configures the @Controller programming model --> 
    <mvc:annotation-driven /> 

    <!-- Resolves view names to protected .jsp resources within the /WEB-INF/views directory --> 
    <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
     <property name="prefix" value="/WEB-INF/jsp/"/> 
     <property name="suffix" value=".jsp"/> 
    </bean> 
</beans> 

这是控制器：

@RequestMapping(value="/AddUser.htm", method=RequestMethod.POST) 
    public @ResponseBody JsonResponse addUser(@ModelAttribute (value="player") Player player, BindingResult result){ 
     JsonResponse res = new JsonResponse(); 
     ValidationUtils.rejectIfEmpty(result, "name", "Name can not be empty."); 
     if(!result.hasErrors()){ 
      htmlPlayerNo++; 
      player.setHtmlPlayerNo(htmlPlayerNo); 
      players.add(player); 
      res.setStatus("SUCCESS"); 
      res.setResult(players); 
     }else{ 
      res.setStatus("FAIL"); 
      res.setResult(result.getAllErrors()); 
     } 
     return res;  
    } 

这些是来自Chrome调试器的头文件：

Request URL:http://localhost:8080/ajaxjqjsbowling/AddUser.htm 
Request Method:POST 
Status Code:406 Not Acceptable 
Request Headersview parsed 
POST /ajaxjqjsbowling/AddUser.htm HTTP/1.1 
Host: localhost:8080 
Connection: keep-alive 
Content-Length: 15 
Accept: */* 
Origin: http://localhost:8080 
X-Requested-With: XMLHttpRequest 
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.31 (KHTML, like Gecko) Chrome/26.0.1410.64 Safari/537.31 
Content-Type: application/x-www-form-urlencoded 
Referer: http://localhost:8080/ajaxjqjsbowling/ 
Accept-Encoding: gzip,deflate,sdch 
Accept-Language: en-US,en;q=0.8 
Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 
Cookie: JSESSIONID=E7FBB01B3FA25CFC091AA539EDFE3CC9 
Form Dataview sourceview URL encoded 
name:John Horan 


Response Headersview parsed 
    HTTP/1.1 406 Not Acceptable 
    Server: Apache-Coyote/1.1 
    Content-Type: text/html;charset=utf-8 
    Content-Length: 1067 
    Date: Mon, 06 May 2013 00:24:53 GMT 

这是我的JQuery代码：

function doAjaxPost() { 
     // get the form values 
     var name = $('#name').val(); 

     $.ajax({ 
     type: "POST", 
     url: contexPath + "/AddUser.htm", 
     data: "name=" + name, 
     success: function(response){ 
      // we have the response 
      if(response.status == "SUCCESS"){ 
       userInfo = "<ol>"; 
       for(var i =0; i < response.result.length ; i++){ 
        userInfo += "<br><li><b>Name</b> : " + response.result[i].name; 
       } 
       userInfo += "</ol>"; 
       $('#info').html("User has been added to the list successfully. " + userInfo); 
       $('#name').val('');   
       $('#error').hide('slow'); 
       $('#info').show('slow'); 
      }else{ 
       errorInfo = ""; 
       for(i =0 ; i < response.result.length ; i++){ 
        errorInfo += "<br>" + (i + 1) +". " + response.result[i].code; 
       } 
       $('#error').html("Please correct following errors: " + errorInfo); 
       $('#info').hide('slow'); 
       $('#error').show('slow'); 
      }  
     }, 
     error: function(e){ 
       alert('Error '+ e); 
     } 
     }); 
    } 

AddUser.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1" 
    pageEncoding="ISO-8859-1"%> 
    <%@taglib uri="http://www.springframework.org/tags/form" prefix="form"%>  

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 
<html> 
<style> 

h1 { 
    font-style: italic; 
    color: green; 
    font-family: Arial, Helvetica, sans-serif; 
    } 

* { 
    color: blue; 
    font-family: Arial, Helvetica, sans-serif; 
} 

</style> 

<head> 
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> 
<title>Ajax Jquery Bowling Game</title> 

<script src="<%=request.getContextPath() %>/js/jquery.js"></script> 

<script type="text/javascript"> 
    var contexPath = "<%=request.getContextPath() %>"; 
</script> 

<script src="<%=request.getContextPath() %>/js/player.js"></script> 

<link rel="stylesheet" type="text/css" href="<%=request.getContextPath() %>/style/app.css"> 
</head> 

<body> 

<div id = "topbox" style="width: 900x; height: 75px; background-color : #B7F39F"> 
<span id = "title"> Ajax-JQuery Bowling</span> 
</div> 

<h1>Welcome to The Bowling App!</h1> 
    <table> 
     <tr><td colspan="2"><div id="error" class="error"></div></td></tr> 
     <tr><td>Enter your name : </td><td> <input type="text" id="name"><br/></td></tr> 
     <tr><td colspan="2"><input type="button" value="Add Users" onclick="doAjaxPost()"><br/></td></tr> 
     <tr><td colspan="2"><div id="info" class="success"></div></td></tr> 
    </table> 
<form:form method="post" action="/ajaxjqjsbowling/showPlay.htm"> 
    <tr> 
     <td colspan="2"> 
      <input type="submit" name = "button" value="Play"/> 
     </td> 
    </tr> 
</form:form> 
</body> 
</html> 

Answer 1

我做的代码返回JSON，但在这样的字符串数据类型格式：

[ 
    { 
     "name": "Jason", 
     "number": "10" 
    }, 
    { 
     "name": "Jimmy", 
     "number": "11" 
    } 
] 

看看为json format here

和功能大致如下：

@RequestMapping(value = "product", method = RequestMethod.GET, headers = "Accept=*/*") 
public @ResponseBody 
String addUser(@RequestParam("term") String query) { 
    String json = "[{\"name\": \"Jason\",\"number\": \"10\" }, {\"name\": \"Jimmy\",\"number\": \"11\" }]"; 
    System.out.println(json); 
    return json; 
} 

我不使用杰克逊或罐子。对不起，我只知道我的方式，可能是别人可以更清楚地解释。