类型错误:this.each不是一个函数默认情况下,我如何从JQgrid中显示子网格?
回报this.each(函数(){这是我的代码从亚格顺序:
subGrid : true,
subGridRowExpanded: function(subgrid_id, row_id) {
//var projectIdRow = $('#list2').jqGrid('getCell',rowId,'projectid');
var subgrid_table_id;
subgrid_table_id = subgrid_id+"_t";
$("#"+subgrid_id).html("<table id='"+subgrid_table_id+"'></table>");
$("#"+subgrid_table_id).jqGrid({
url:"/taskuri/subGrid/?id="+row_id,
datatype: "json",
colNames: ['SubTask',' ','Pri','Responsabil','Alocator','Alocat','Deadline','Estimat','Lucrat',' '],
colModel: [
{name:"SubTask",index:"SubTask",width:'687%',align:"left",sortable:false},
{name:'finished',index:'finished', width:'40%',sortable:false},
{name:"Pri",index:"Pri",width:'56%', sortable:true},
{name:"Responsabil",index:"Responsabil",width:'128%',sortable:false},
{name:"Alocator",index:"Alocator",width:'130%',sortable:false},
{name:"Alocat",index:"Alocat",width:'110%',sortable:false},
{name:"Deadline",index:"Deadline",width:'110%',sortable:false},
{name:"Estimat",index:"Estimat",width:'76%',align:"right",sortable:false},
{name:"Lucrat",index:"Lucrat",width:'90%',align:"right"},
{name:"Delete",index:"Delete",width:'90%',align:"right"},
],
height: '100%',
rowNum:20,
});
},
我想要的东西首先显示次网格默认情况下(当我访问页面时);其次,如果没有数据,那么没有点显示子网格,我该怎么做?下面我上传一个图像,看看它是如何显示的,如果没有数据。thx
我试过这个方法:
gridComplete: function(){
var grid = $("#list2");
var svi_id = grid.jqGrid('getDataIDs');
$.each(svi_id, function (index, rowId) {
$(this).jqGrid.expandSubGridRow(rowId);
// or grid.jqGrid.expandSubGridRow(rowId);
});
},
并且结果是错误:TypeError:this.each不是函数 返回this.each(function(){{(firebug)。哪里不对 ?
你可以给我一个例子,子网格正确的代码? thx – Chester
我更新了我的帖子,请检查它 – Chester