Java卡处理程序

Question

我正在写一个程序，做一个卡技巧，但首先我必须弄清楚如何处理3行7张卡。我无法弄清楚为什么当我运行我的程序时，它只输出所有卡的一个数字，以及如何让它打印出卡的名称。我可以用PrintCard（）函数打印52张独特的卡片，但在使用Deal（）时不能打印，我不知道为什么会有任何帮助。谢谢。

这是目前我的代码：

import java.util.Random; 

public class testing { 

    public static void main(String[] args) { 
    testing cs = new testing();  
    int [] deck = new int [52]; 
    int [] [] play = new int [7] [3]; 
    cs.BuildDeck (deck); 
    cs.Deal(deck, play); 
    } 

    public static void BuildDeck(int deck[]) { 
     int[] used = new int[52]; 
     int card = 0; 
     int i = 0; 
     /* 
     * Generate cards until the deck is full of integers 
     */ 
     while (i < deck.length) { 
      /* 
      * generate a random number between 0 and 51 
      */ 
      Random random1 = new Random(); 
      card = (random1.nextInt(52) % 52); 
      /* 
      * Check the used array at the position of the card. If 0, add the card and set the used location 
      * to 1. If 1, generate another number 
      */ 
      if (used[card] == 0) { 
       used[card] = 1; 
       deck[i] = card; 
       i++; 
      } 
     } 
    } 

    public static void PrintCard(int card) { 
     int rank = (card % 13); 
     int suit = (card/13); 
     String[] suits = {"Clubs", "Hearts", "Diamonds", "Spades"}; 
     String[] ranks = {"King", "Ace", "2", "3", "4", "5", "6", 
      "7", "8", "9", "10", "Jack", "Queen"}; 

     System.out.println(ranks[rank] + " of " + suits[suit]); 
    } 

    public static void Deal(int deck[], int play[][]) { 
     int card = 0; 
System.out.println ("\n Column 0   Column 1   Column 2"); 
System.out.println ("=======================================================\n"); 
for (int row = 0; row < play.length; row++) { 
    for (int col = 0; col < play [row].length; col++) { 
     play[row][col] = deck[card++]; 
     System.out.print("  " + play[row][col] + "   "); 

    } 
    System.out.println(); 
     } 
    } 
} 

更大的计划：http://pastebin.com/99tLpVjM

Answer 1

在交易中，你永远不会用卡做什么。使其迭代。

public void deal (int deck [], int play [] []) { 
    /* 
    * deal cards by passing addresses of cardvalues from the deck array to the play array 
    */ 
    int card = 0; 
    System.out.println ("\n Column 0   Column 1   Column 2"); 
    System.out.println ("=======================================================\n"); 
    for (int row = 0; row < play.length; row++) { 
     for (int col = 0; col < play [row].length; col++) { 
      play [row] [col] = deck [card++]; 
      System.out.print ("\t" + printCard (card) + "\t"); 
     } 
     System.out.println(); 
    } 
} 

因此，申报随机的一流水平：

Random random1 = new Random(); 

public static void main (String [] args) { 
    CardShuffle cs = new CardShuffle(); 
    int [] deck = new int [52]; 
    int [] [] play = new int [7] [3]; 
    cs.buildDeck (deck); 
    cs.deal (deck, play); 
} 

不要让一切静止。 你不需要模52位置：

int card = random1.nextInt (52); 

输出：

Column 0   Column 1   Column 2 
====================================================== 
    18    7    2   
    47    11    34   
    0    45    26   
    10    9    41   
    35    31    23   
    16    22    39   
    4    8    50  

注意，我重命名的文件和类CardShuffle，所以它不会覆盖其他2000 testing.java-文件。 如果printCard将返回一个字符串，您可以从deal打印它。

Answer 2

在第63行你写play[row][col]=deck[card];但你永远不会改变/增加可变card，所以你总是从获取第一card您deck，因为card始终为0。

Answer 3

你有方法PrintCard()以可读的格式输出卡片，但是你根本不在程序中调用这个方法。