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我们有一串数据通过卡夫卡主题。我读过使用Spark Streaming。Spark Streaming - Kafka- createStream - RDD到数据帧
val ssc = new StreamingContext(l_sparkcontext, Seconds(30))
val kafkaStream = KafkaUtils.createStream(ssc, "xxxx.xx.xx.com:2181", "new-spark-streaming-group", Map("event_log" -> 10))
这很好用。我想要的是通过将列分配给流数据来编写Parquet文件。因此,我做以下
kafkaStream.foreachRDD(rdd => {
if (rdd.count() == 0) {
println("No new SKU's received in this time interval " + Calendar.getInstance().getTime())
}
else {
println("No of SKUs received " + rdd.count())
rdd.map(record => {
record._2
}).toDF("customer_id","sku","type","event","control_group","event_date").write.mode(SaveMode.Append).format("parquet").save(outputPath)
然而,这给出了一个错误
java.lang.IllegalArgumentException: requirement failed: The number of columns doesn't match.
Old column names (1): _1
New column names (6): customer_id, sku, type, event, control_group, event_date
at scala.Predef$.require(Predef.scala:233)
at org.apache.spark.sql.DataFrame.toDF(DataFrame.scala:224)
at org.apache.spark.sql.DataFrameHolder.toDF(DataFrameHolder.scala:36)
at kafka_receive_messages$$anonfun$main$1.apply(kafka_receive_messages.scala:77)
at kafka_receive_messages$$anonfun$main$1.apply(kafka_receive_messages.scala:69)
那是什么我想提出请错误。我们是否应该在地图上分割?如果我们这样做,那么我们不会将它转换为DF(“..列..”)
感谢您的帮助。
问候
巴拉