Python：简化计数程序

Question

我对Python非常陌生，并且提出了一个程序，要求用户选择2个数字。第一个必须介于1和10之间，第二个必须介于100和200之间。程序然后要求用户选择介于1和5之间的第三个数字。分别调用这3个数字X，Y和Z然后，程序从X到Y的步长为Z.

预期行为：如果用户选择了10,105和5，那么Python应打印15,20,25等等，最大为105.此外，如果用户尝试如果输入的值超出程序指定的值，它将拒绝输入并要求用户再次尝试。

该程序的工作原理如我所说，我对Python非常陌生，所以如果我已经以最优化的方式完成，我会感到非常惊讶。你认为无论如何简化下面的代码，使其更有效率？

下面的代码：

x = int(input("Please enter any number between 1 and 10: ").strip()) 

while x > 10 or x < 1: 
    print("No! I need a number between 1 and 10.") 
    x = int(input("Please enter any number between 1 and 10: ").strip()) 

y = int(input("Now enter a second number between 100 and 200: ").strip()) 

while y > 200 or y < 100: 
    print("No! I need a number between 100 and 200.") 
    y = int(input("Please enter any number between 100 and 200: ").strip()) 

print("Now we're going to count up from the first to the second number.") 
print("You can count every number, every second number, and so on. It's up to you.") 
z = int(input("Enter a number between 1 and 5: ").strip()) 

while z > 5 or z < 1: 
    print("No. I need a number between 1 and 5!") 
    z = int(input("Enter a number between 1 and 5: ").strip()) 

print("You have chosen to count from {} to {} in steps of {}.".format(x, y, z)) 

input("\nPress Enter to begin") 

for q in range(x,y): 
    if q == x + z: 
    print(q) 
    x = x + z 

程序工作，但我的直觉告诉我，必须有这样做一个更清洁的方式。你可能会有任何建议将大量赞赏。

干杯！

Answer 1

您可以替换循环：

for q in range(x,y,z): 
    print(q) 

添加第三个参数的范围内表达使其逐步计数。

Answer 2

好吧，我爱压缩码，我喜欢挑战sooooooooo，

BAM CODE：

x, y, z = None, None, None 
while x == None or x > 10 or x < 1: x = int(input("Please enter any number between 1 and 10: ")) 
while y == None or y > 200 or y < 100: y = int(input("Please enter any number between 100 and 200: ")) 
print("Now we're going to count up from the first to the second number."+'\n'+"You can count every number, every second number, and so on. It's up to you.") 
while z == None or z > 5 or z < 1: z = int(input("Enter a number between 1 and 5: ")) 
tmp=raw_input(str("You have chosen to count from {} to {} in steps of {}.".format(x, y, z))+'\n'+"Press Enter to begin") 
x = x-1 
for q in range(x,y,z): print(q) 
print x+z 

紧凑，我能做到。