猫鼬：查找和过滤嵌套数组

Question

我试图找到一个带有Find()命令的整个文档，并用条件过滤嵌套数组。

这里一块使用模式的：

var ListSH = new Schema({ 
    name: { type: String, unique: true, required: true}, 
    subject : String, 
    recipients : [ 
    Schema({ 
    uid : { type : ObjectId, required : true, ref:'User', unique: true}, 
    status : { type : Number, default : 1 } 
    },{_id: false}) 
    ] 
}; 

目前我做ListModel.findOne({ _id : req.params.id_list, function(err,list){...};

和送信给我说：

{ 
    "_id": "57e6bcab6b383120f0395aed", 
    "name": "Emailing listname", 
    "subject": "List subject", 
    "recipients": [ 
    { 
     "uid": "57e932bcbbf0e9e543def600", 
     "status": 0 
    }, 
    { 
     "uid": "57e93266c3c0b1dc1625986f", 
     "status": 1 
    } 
    ] 
} 

我想邮差回到我喜欢的东西即通过加入recipients.status : 1条件

{ 
     "_id": "57e6bcab6b383120f0395aed", 
     "name": "Emailing listname", 
     "subject": "List subject", 
     "recipients": [ 
     { 
      "uid": "57e93266c3c0b1dc1625986f", 
      "status": 1 
     } 
     ] 
    } 

我已经尝试过ListModel.findOne({ _id : req.params.id_list, 'recipients.status' : 1}, function(err,list){...};

和奇怪的东西像populate([$match('recipients.status : 1)]); 但没有成功..

有谁知道？ 谢谢^^

Answer 1

您可以使用aggregate得到它在一个简单的方法是这样

ListModel.aggregate(
    { $match: {_id: ObjectId("57e6bcab6b383120f0395aed")}}, 
    { $unwind: '$recipients'}, 
    { $match: {'recipients.status':1}}) 

输出

{ 
    "_id" : ObjectId("57e6bcab6b383120f0395aed"), 
    "name" : "Emailing listname", 
    "subject" : "List subject", 
    "recipients" : { 
     "uid" : "57e93266c3c0b1dc1625986f", 
     "status" : 1 
    } 
} 

要详细了解汇总，请参阅文档s here

Answer 2

试试下面的查询：

ListModel.findOne({"_id" : "57e6bcab6b383120f0395aed", 'recipients.status' : 1},{_id:1, name: 1, subject:1,'recipients.$': 1}, function(err,list){...});