如何选择*并获得按字母顺序排列的所有字段

Question

这可能是一个奇怪的问题。

我有一个100 +列的表。我想SELECT *所有列，并获得与列按字母顺序排列的结果查询。

在T-SQL中可能吗？

感谢

Answer 1

你可以建立使用在系统目录视图提供的信息，动态SQL语句。

下面的代码示例演示如何：

DECLARE @sql AS NVARCHAR(MAX) 
DECLARE @cols AS NVARCHAR(MAX) 

DECLARE @tbl NVARCHAR(MAX) = N'your_table' -- this is your source table 

SELECT @cols= ISNULL(@cols + ',','') + QUOTENAME(c.name) 
FROM sys.tables t 
join sys.columns c ON c.object_id = t.object_id 
WHERE t.name = @tbl 
ORDER BY c.name 

SET @sql = N'SELECT ' + @cols + ' FROM ' + @tbl 
EXEC sp_executesql @sql 

Answer 2

DynamicSQL（SQL Server）的例子：你

declare @TABLE varchar(200) set @TABLE='persons' 
declare @SQL nvarchar(max) 
set @SQL='select ' 
select @SQL= @SQL + column_name + ',' 
from information_schema.columns where table_name=@TABLE order by column_name 
select @SQL = left(@SQL,len(@SQL)-1) + ' from ' + @TABLE -- trims the trailing comma 

--select @SQL -- If you want to see the query 

exec sp_executesql @SQL 

Answer 3

DECLARE @Table NVARCHAR(MAX)='T'--pass your table name 
DECLARE @SQL NVARCHAR(MAX)='SELECT ' 
SELECT @SQL=@SQL+',' +NAME FROM 
(
SELECT TOP 100 QUOTENAME(NAME) AS NAME 
FROM sys.columns 
WHERE object_id = 
(
SELECT OBJECT_ID FROM sys.tables 
WHERE NAME =@Table 
) 
ORDER BY NAME 
) AS SS 


SELECT @SQL=STUFF(@SQL,8,1,'')+' FROM '+@Table 


EXEC sp_executesql @sql