0
磨砂（即选择）元素我下面两个教程：无法识别或程式化的D3
但我似乎无法识别或选择的风格化（即刷）元素。我怀疑某些类型的范围问题。
这里是我的代码：
<!DOCTYPE html>
<head>
<meta charset="utf-8">
<style>
.node {
stroke: #fff;
stroke-width: 1.5px;
}
.node .selected {
stroke: #ff0;
}
.link {
stroke: #999;
stroke-opacity: .6;
}
.brush .extent {
stroke: #fff;
fill-opacity: 0.2;
shape-rendering: crispEdges;
}
</style>
</head>
<body>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
var force = d3.layout.force()
.gravity(0.1)
.linkStrength(0.1)
.charge(-50)
.linkDistance(25)
.size([window.innerWidth, window.innerHeight]);
var svg = d3.select("body").append("svg")
.attr("width", window.innerWidth)
.attr("height", window.innerHeight);
d3.json("graph.json", function(error, graph) {
force
.nodes(graph.nodes)
.links(graph.links)
.start();
var link = svg.append("g").attr("class", "link")
.selectAll("line")
.data(graph.links)
.enter().append("line")
.style("stroke-width", 1);
var node = svg.append("g").attr("class", "node")
.selectAll("circle")
.data(graph.nodes)
.enter().append("circle")
.attr("r", 5);
var brush = svg.append("g").attr("class", "brush")
.call(d3.svg.brush()
.x(d3.scale.identity().domain([0, window.innerWidth]))
.y(d3.scale.identity().domain([0, window.innerHeight]))
.on("brush", function() { // Here be dragons
var extent = d3.event.target.extent();
node.classed("selected", function (d) {
return extent[0][0] <= d.x && d.x < extent[1][0]
&& extent[0][1] <= d.y && d.y < extent[1][1];
});
}));
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
});
});
</script>
</body>
</html>
这里是graph.json：
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在控制台运行$('.selected')与区域突出显示收益率只有1种中选择元素，尽管多大刷面积是。任何帮助将非常欢迎！