有人能告诉我什么,我需要做的解决这个XMLParsing - 字符串转换为NSNumber的
- 我有一个对象使用者偏好*用户偏好
- 有一个变量,名为userpref.userid,它是一个NSNumber的
- 我解析XML,直到我去我的“myxmluseridnumber”元素分配给userpref.userid
这是错误的信息在这里一切正常良好。
不兼容的指针类型,把 '的NSMutableString * _strong' 到类型的参数“的NSNumber
- (void) parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict {
if ([elementName isEqualToString:@"User"]) {
inItemElement = YES;
}
if (inItemElement && [elementName isEqualToString:@"myxmluseridnumber"]) {
capturedCharacters = [[NSMutableString alloc] initWithCapacity:100];
}
}
- (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string {
if(capturedCharacters != nil) {
[capturedCharacters appendString:string];
}
}
- (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName {
if (inItemElement && [elementName isEqualToString:@"myxmluseridnumber"]) {
NSLog(@"%@ - myxmlnumber", capturedCharacters);
//This is what is producing my error
userpref.userid = capturedCharacters;
capturedCharacters = nil;
}
if ([elementName isEqualToString:@"User"]) {
inItemElement = NO;
}
}
感谢
这一个很好,谢谢! – Harpua 2012-01-12 15:32:26