我必须做的登录表单验证，如果密码匹配，将前进

Question

it is moving forward on any user name or password.let me know the correct solution for this. 

这是我dao.java类

public List <Student> getLogin() { 
    return template.query("select * from auction", new RowMapper <Student>() { 

    @Override 
    public Student mapRow(ResultSet rs, int row) throws SQLException { 
     Student s = new Student(); 
     s.setName(rs.getString(1)) 
     s.setPassword(rs.getString(2)); 

     return s; 
    } 
    }); 
} 

这是我controller.java亲切纠正我的代码....什么我需要做的一些更改

@RequestMapping(value="/addLogin",method=RequestMethod.GET) 
public String addLogin(@ModelAttribute("SpringWeb")Student s, Model model) { 
    List<Student> list=dao.getLogin(); 
    List <Student> b=dao.getStudentRecord(); 
    String name=s.getName(); 
    String password=s.getPassword(); 
    if(name.equals(list) && password.equals(list)) { 
    model.addAttribute("welcome",name); 
    model.addAttribute("record",b); 
    return "change"; 
    } else { 
    model.addAttribute("login","Wrong Username or Password"); 
    return "login"; 
    } 
} 

Answer 1

您不需要查询所有用户进行登录。而不是将查询更改为

"select * from auction where userName=? and password=?" 

在服务中检查查询是否返回任何行。如果查询返回一行，则登录成功，否则登录失败。

所以春季实现变得..

template.queryForList("select * from auction where userName=? and password=?", new Object[]{userName, password});