XML保存所有的孩子可变

Question

我使用jQuery AJAX得到一个XML文件：

$.ajax({ 
      type: "GET", 
      url: phoneXmlPath, 
      dataType: "xml", 
      contentType: "text/xml; charset=utf-8", 
      success: function(xml){ 
       $(xml).find("phone[phone_id="+phone_id+"]").each(function(index, value){ 
        var tis = $(this); 
        tis.children().each(function(){ 
         alert($(this).nodeName); 
        }); 
       }); 

      }, 
      error:function(xhr,type){ 
       if(type == null){ 
        var errorMsg = "There was an error loading the phone.xml file!<br/>Please make sure the path to the xml file <strong>'"+phoneXmlPath+"'</strong> is correct."; 
       }else if(type == "parsererror"){ 
        var errorMsg = "There is an error in the file <strong>'"+phoneXmlPath+"'</strong>."; 
       }else{ 
        var errorMsg = "An error has been detected."; 
       }  
       popup.removeClass("loading").html("<p><strong>Error:</strong> "+errorMsg+"</p><p><strong>Type of error:</strong> "+type+".</p>");  
      }   
     }); 

在这一部分：alert($(this).nodeName);我怎么能保存所有的变量，我以后可以访问。例如，我希望能够做到的代码：“phone.title”，并访问所有电话儿童元素。

XML文件

<phones> 
<phone> 
    <phone_id>123</phone_id> 
    <title>Phone title</title> 
    etc.... 

Answer 1

使用JavaScript XML解析器 - http://www.w3schools.com/xml/xml_parser.asp