ng选择的表达式不选择时为真

当accommodation的索引为0时，则将选定的attribute添加到选项中。我不确定我做错了什么。ng选择的表达式不选择时为真

以下是我与

<select formControlName="type" required> 
    <option value="{{ accommodation.id }}" *ngFor="let accommodation of ListAccommodationTypes; let i = index;" ng-selected="0 in i">{{ accommodation.name }}</option> 
</select>

工作代码这是它呈现在DOM

<select formcontrolname="type" required="" ng-reflect-name="type" class="ng-untouched ng-pristine ng-invalid"> 
    <!--template bindings={ 
     "ng-reflect-ng-for-of": "[object Object],[object Object],[object Object],[object Object],[object Object]" 
     }--> 
    <option ng-selected="0 in i" value="4" ng-reflect-value="4">Something 4</option> 
    <option ng-selected="0 in i" value="5" ng-reflect-value="5">Something 5</option> 
    <option ng-selected="0 in i" value="3" ng-reflect-value="3">Something 3</option> 
    <option ng-selected="0 in i" value="2" ng-reflect-value="2">Something 2</option> 
    <option ng-selected="0 in i" value="1" ng-reflect-value="1">Something 1</option> 
</select>

我也曾尝试

<select formControlName="type" required> 
    <option value="{{ accommodation.id }}" *ngFor="let accommodation of ListAccommodationTypes; let i = index;" ng-selected="i==0">{{ accommodation.name }}</option> 
</select> 

<select formControlName="type" required> 
    <option value="{{ accommodation.id }}" *ngFor="let accommodation of ListAccommodationTypes; let i = index;" ng-selected="{{i==0}}">{{ accommodation.name }}</option> 
</select>

来源

2017-02-15 Devil Raily

试试这个

<option *ngFor="let accommodation of ListAccommodationTypes; let i = index;" 
    [attr.selected]="i == 0 ? true : null"> 
    {{ accommodation.name }} 
</option>

来源

2017-02-15 01:41:50 digit

ng选择的表达式不选择时为真

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