我想写一个网页,会遍历一个指定的目录....并获得在该目录中的所有文件...PHP - 代码遍历目录,并获得所有文件(影像)
在我的情况下,该目录将只包含图像,并与他们的链接显示图片...
像这样
怎么办呢
p.s.该目录将不会被用户输入..它将始终是相同的目录...
我想写一个网页,会遍历一个指定的目录....并获得在该目录中的所有文件...PHP - 代码遍历目录,并获得所有文件(影像)
在我的情况下,该目录将只包含图像,并与他们的链接显示图片...
像这样
怎么办呢
p.s.该目录将不会被用户输入..它将始终是相同的目录...
/**
* function get files
* @param $path string = path to fine files in
* @param $accept array = array of extensions to accept
* @param currentLevel = 0, stopLevel = 0
* @return array of madmanFile objects, but you can modify it to
* return whatever suits your needs.
*/
public static function getFiles($path = '.', $accept, $currentLevel = 0, $stopLevel = 0){
$path = trim($path); //trim whitespcae if any
if(substr($path,-1)=='/'){$path = substr($path,0,-1);} //cutoff the last "/" on path if provided
$selectedFiles = array();
try{
//ignore these files/folders
$ignoreRegexp = "/\.(T|t)rash/";
$ignore = array('cgi-bin', '.', '..', '.svn');
$dh = @opendir($path);
//Loop through the directory
while(false !== ($file = readdir($dh))){
// Check that this file is not to be ignored
if(!in_array($file, $ignore) and !preg_match($ignoreRegexp,$file)){
$spaces = str_repeat(' ', ($currentLevel * 4));
// Its a directory, so we need to keep reading down...
if(is_dir("$path/$file")){
//merge current selectFiles array with recursion return which is
//another array of selectedFiles
$selectedFiles = array_merge($selectedFiles,MadmanFileManager::getFiles("$path/$file", $accept, ($currentLe$
} else{
$info = pathinfo($file);
if(in_array($info['extension'], $accept)){
$selectedFiles[] = new MadmanFile($info['filename'], $info['extension'], MadmanFileManager::getSize($
}//end if in array
}//end if/else is_dir
}
}//end while
closedir($dh);
// Close the directory handle
}catch (Exception $e){
echo 'Caught exception: ', $e->getMessage(), "\n";
}
return $selectedFiles;
}
您将要使用scandir函数来遍历目录中的文件列表。
if ($handle = opendir('.')) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != "..") {
echo "$file\n";
}
}
closedir($handle);
}
使用readdir
+1,为答案。 – 2013-09-21 08:19:06
$dir = "/etc/php5/";
//打开一个已知的目录,并继续阅读其内容
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
echo "filename: $file : filetype: " . filetype($dir . $file) . "\n";
}
closedir($dh);
}
}
你可以像其他人建议检查目录中的每个文件,或者你可以使用glob来识别基于扩展名的文件。
我用线沿线的东西:
if ($dir = dir('images'))
{
while(false !== ($file = $dir->read()))
{
if (!is_dir($file) && $file !== '.' && $file !== '..' && (substr($file, -3) === 'jpg' || substr($file, -3) === 'png' || substr($file, -3) === 'gif'))
{
// do stuff with the images
}
}
}
else { echo "Could not open directory"; }
你也可以尝试glob功能:
$path = '/your/path/';
$pattern = '*.{gif,jpg,jpeg,png}';
$images = glob($path . $pattern, GLOB_BRACE);
print_r($images);
嗨,你可以使用DirectoryIterator
try {
$dir = './';
/* @var $Item DirectoryIterator */
foreach (new DirectoryIterator($dir) as $Item) {
if($Item->isFile()) {
echo $Item->getFilename() . "\n";
}
}
} catch (Exception $e) {
echo 'No files Found!<br />';
}
如果你想递归地传递目录: http://php.net/manual/en/class.recursivedirectoryiterator.php
<?php
//define directory
$dir = "images/";
//open directory
if ($opendir = opendir($dir)){
//read directory
while(($file = readdir($opendir))!= FALSE){
if($file!="." && $file!= ".."){
echo "<img src='$dir/$file' width='80' height='90'><br />";
}
}
}
?>
来源:
function recurseDir ($dir) {
// open the provided directory
if ($handle = opendir($_SERVER['DOCUMENT_ROOT'].$dir)) {
// we dont want the directory we are in or the parent directory
if ($entry !== "." && $entry !== "..") {
// recursively call the function, if we find a directory
if (is_dir($_SERVER['DOCUMENT_ROOT'].$dir.$entry)) {
recurseDir($dir.$entry);
}
else {
// else we dont find a directory, in which case we have a file
// now we can output anything we want here for each file
// in your case we want to output all the images with the path under it
echo "<img src='".$dir.$entry."'>";
echo "<div><a href='".$dir.$entry."'>".$dir.$entry."</a></div>";
}
}
}
}
的$ DIR PARAM需要在以下格式: “/路径/” phpacademy.org
我将通过创建一个递归函数开始或“/ path/to/files /”
基本上,只是不包括服务器根,因为我已经在下面使用$ _SERVER ['DOCUMENT_ROOT “]。
因此,最后只需调用我们刚刚在代码中创建的recurseDir函数一次,它将遍历任何子文件夹并将图像与其下的链接一起输出。
可能的[从文件夹加载图像列表](http://stackoverflow.com/questions/758594/load-list-of-image-from-folder)和[更多](http:// stackoverflow .com/search?q = get + all + images + in + a + folder + php) – Gordon 2010-08-31 11:06:37
*(相关)* http://stackoverflow.com/questions/3563863/read-files-in-folder/3564311#3564311 – Gordon 2010-08-31 11:50:13