如何显示在消息框中的用户ID，如果微调值选择

Question

我想告诉我的用户ID 消息框但微调选择则显示ID，但ID不会不显示值。这是我的代码。

主要类代码：

public class AgentProgress extends Activity { 

Spinner sp1, sp2; 
ListView ls1; 
ProgressBar pbbar; 
ArrayList<String> names = new ArrayList<String>(); 
ArrayList<AgentID> web; 
ArrayList<String> wordlist; 
ArrayAdapter<String> adaptername; 
ArrayList<HashMap<String, String>> menuItems1 = new ArrayList<HashMap<String, String>>(); 
static final String KEY_TABLE = "AGENTDATA"; 
static final String KEY_AMOUNT = "Parent_Agent_Name"; 
static final String KEY_USER = "Parent_Agent_Id_Pk"; 


@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_agent_progress); 

    sp1 = (Spinner) findViewById(R.id.spnames); 
    sp2 = (Spinner) findViewById(R.id.spyear); 

    ArrayList<String> years = new ArrayList<String>(); 

    int thisYear = Calendar.getInstance().get(Calendar.YEAR); 
    for (int i = thisYear; i >= 2011; i--) { 
     years.add(Integer.toString(i)); 
    } 
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, 
      android.R.layout.simple_spinner_item, years); 


    sp2.setAdapter(adapter); 


    pbbar = (ProgressBar) findViewById(R.id.pbbar); 
    pbbar.setVisibility(View.GONE); 

    ArrayList<HashMap<String, String>> menuItems = new ArrayList<HashMap<String, String>>(); 

    try { 
     web = new ArrayList<AgentID>(); 
     wordlist = new ArrayList<String>(); 

     if (connectionAvailable() == true) { 

      StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder() 
        .permitAll().build(); 

      StrictMode.setThreadPolicy(policy); 

      WebServiceCAll com = new WebServiceCAll(); 

      AgentID agent = new AgentID(); 
      // final String string1 = getIntent().getStringExtra("Agentid"); 

      String strXml = com.LoadAgent("LoadAgent"); 

      //messageBox("test", strXml); 
      XMLParser parser = new XMLParser(); 
      Document doc = parser.getDomElement(strXml); // getting DOM element 

      NodeList nl = doc.getElementsByTagName(KEY_TABLE); 
      //String[] arList = null; 
      //String[] arListkey = null; 
      // int conttotal=0; 
      // looping through all item nodes <item> 


      for (int j = 0; j < nl.getLength(); j++) { 

       // creating new HashMap 


       Map<String, String> map = new HashMap<String, String>(); 
       // adding each child node to HashMap key => value 
       //map.put(KEY_AMOUNT, parser.getValue(e, KEY_AMOUNT)); 
       //map.put(KEY_USER,parser.getValue(e,KEY_USER)); 
       // adding HashList to ArrayList 
       //menuItems.add(map); 

       Element e = (Element) nl.item(j); 
       //messageBox("test", "fahad"); 
       agent.setID(map.put(KEY_USER, parser.getValue(e, KEY_USER))); 
       agent.setname(map.put(KEY_AMOUNT, parser.getValue(e, KEY_AMOUNT))); 
       names.add(map.put(KEY_AMOUNT, parser.getValue(e, KEY_AMOUNT))); 


      } 


     } else { 
      messageBox("ERROR", "No Internet Service"); 
     } 


    } catch (Exception ex) { 

    } 


    adaptername = new ArrayAdapter<String>(this, android.R.layout.simple_spinner_item, names); 
    sp1.setAdapter(adaptername); 
    AgentProgress.this.runOnUiThread(new Runnable() { 
     @Override 
     public void run() { 
      adaptername.notifyDataSetChanged(); 
     } 
    }); 


    sp1.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() { 
     @Override 
     public void onItemSelected(AdapterView<?> adapterView, View view, int agr, long l) { 

      HashMap<String,Object> obj=(HashMap<String,Object>) adaptername.getItem(agr); 

      String pr=(String) obj.get(KEY_USER); 

      messageBox("",pr); 
     } 

     @Override 
     public void onNothingSelected(AdapterView<?> adapterView) { 

     } 
    }); 




} 


     private void messageBox(String method, String message) { 
      AlertDialog.Builder messageBox = new AlertDialog.Builder(this); 
      messageBox.setTitle(method); 
      messageBox.setMessage(message); 
      messageBox.setCancelable(false); 
      messageBox.setNeutralButton("OK", null); 
      messageBox.show(); 
     } 

     private boolean connectionAvailable() { 
      boolean connected = false; 
      ConnectivityManager connectivityManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE); 
      if (connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE).getState() == NetworkInfo.State.CONNECTED || 
        connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI).getState() == NetworkInfo.State.CONNECTED || 
        connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE_SUPL).getState() == NetworkInfo.State.CONNECTED) { 
       //we are connected to a network 
       connected = true; 
      } 
      return connected; 
} 
} 

它显示并在哈希表出错项目选择监听错误消息是：

incompatible types: String cannot be converted to HashMap<String,Object> 

Answer 1

您正试图获得Item没有得到一个Adapter。

更换

HashMap<String,Object> obj=(HashMap<String,Object>) adaptername.getItem(agr); 

与

HashMap<String,Object> obj=(HashMap<String,Object>) adapterView.getAdapter().getItem(agr);