的XPath：选择以下所有节点，直到某个节点

我尝试下面解析结构成套旅程选项，这样我可以找出所有可能的方式获得距离Pontypridd到兰戈伦和背部。的XPath：选择以下所有节点，直到某个节点

使用XPath，我可以做//div[@class='JourneyOptions']来选择实际包含旅程信息的所有行。在XPath之外，我可以遍历每一行来决定是否应将其添加到一组旅程中，或者它是否是一组新旅程中的第一个。

在下面的示例中，所有的旅程集将包含两个行程，而是一组可以包含仅一个旅程（“直接”旅程），或两个以上的（一个以上的“连接”）。

是否有XPath表达式来选择第一个出站集的所有行程，第二个出站集的所有行程等等？

每个集合中的第一个旅程都有一个带有整数值的无线电输入。我可以动态生成这些来标记每个集合，但是需要知道何时停止生成（或者只是等待XPath失败）。

<div class='TableHolder'> 

    <p>...</p> 
    <h2 id='DirectionHeader'>Outbound Options</h2> 
    <p>Pontypridd to Llangollen, 30/11/1910</p> 

    <!-- first part of the first journey from Pontypridd to Llangollen --> 
    <div class='JourneyOptions'> 
    <div class='Journey'> 
     <div class='ColumnOne'> 
      <input type='radio' checked='checked' name='out' value='1'> 
     </div> 
     ... some more divs of parseable journey info ... 
    </div> 
    <div> 

    <!-- second part of the first journey from Pontypridd to Llangollen --> 
    <div class='JourneyOptions'> 
    <div class='Journey'> 
     <div class='ConnectingJournies'> 
      <p>...</p> 
     </div> 
     <div class='ColumnOne'> 
      ... doesn't contain a radio input ... 
     </div> 
     ... some more divs of parseable journey info ... 
    </div> 
    </div> 

    <!-- first part of the second journey from Pontypridd to Llangollen --> 
    <div class='JourneyOptions'> 
    <div class='Journey'> 
     <div class='ColumnOne'> 
      <input type='radio' name='out' value='2'> 
     </div> 
     ... some more divs of parseable journey info ... 
    </div> 
    <div> 

    <!-- second part of the second journey from Pontypridd to Llangollen --> 
    <div class='JourneyOptions'> 
    <div class='Journey'> 
     <div class='ConnectingJournies'> 
      <p>...</p> 
     </div> 
     <div class='ColumnOne'> 
      ... doesn't contain a radio input ... 
     </div> 
     ... some more divs of parseable journey info ... 
    </div> 
    </div> 

    ... some more outbound journey options ... 

    <p>...</p> 
    <h2 id='DirectionHeader'>Inbound Options</h2> 
    <p>Llangollen to Pontypridd, 07/11/1910</p> 

    <!-- first part of the first journey from Llangollen to Pontypridd --> 
    <div class='JourneyOptions'> 
    <div class='Journey'> 
     <div class='ColumnOne'> 
      <input type='radio' checked='checked' name='in' value='1'> 
     </div> 
     ... some more divs of parseable journey info ... 
    </div> 
    <div> 

    <!-- second part of the first journey from Llangollen to Pontypridd --> 
    <div class='JourneyOptions'> 
    <div class='Journey'> 
     <div class='ConnectingJournies'> 
      <p>...</p> 
     </div> 
     <div class='ColumnOne'> 
      ... doesn't contain a radio input ... 
     </div> 
     ... some more divs of parseable journey info ... 
    </div> 
    </div> 

    <!-- first part of the second journey from Llangollen to Pontypridd --> 
    <div class='JourneyOptions'> 
    <div class='Journey'> 
     <div class='ColumnOne'> 
      <input type='radio' name='in' value='2'> 
     </div> 
     ... some more divs of parseable journey info ... 
    </div> 
    <div> 

    <!-- second part of the second journey from Llangollen to Pontypridd --> 
    <div class='JourneyOptions'> 
    <div class='Journey'> 
     <div class='ConnectingJournies'> 
      <p>...</p> 
     </div> 
     <div class='ColumnOne'> 
      ... doesn't contain a radio input ... 
     </div> 
     ... some more divs of parseable journey info ... 
    </div> 
    </div> 

    ... some more inbound journey options ... 
</div>

很抱歉的大例子，但我认为这是小我可以把它同时仍然代表我的问题。

来源

2010-11-30 Iain Elder

节点集恰好......集：主机语言依赖性排序（最多的文档顺序）唯一节点。如果你想要表达某种层次或分组的结果，答案是你不能。

所以，你可以选择各组与启动：当时

/div[@class='TableHolder'] 
    /div[@class='JourneyOptions'] 
     [div[@class='Journey'] 
      /div[@class='ColumnOne'] 
       /input[@type='radio'] 
     ]

一组（有很多选择）：

/div[@class='TableHolder'] 
    /div[@class='JourneyOptions'] 
     [count(
      (self::div|preceding-sibling::div) 
       [div[@class='Journey'] 
        /div[@class='ColumnOne'] 
         /input[@type='radio'] 
       ] 
      ) = 1 
     ]

来源

2010-11-30 12:52:00

的XPath：选择以下所有节点，直到某个节点

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