2011-10-31 107 views
1

我有一个具有2个子类型的地址实体。这里是我的简化代码:如何使用AutoMapper映射到具有继承和嵌套模型的模型

public class Address { 
    public string Street1 { get; set; } 
    public string Country { get; set; } 
} 
public class UsAddress : Address { 
    public string State { get; set; } 
} 
public class CandianAddress : Address { 
    public string Providence { get; set; } 
} 

这里是我的简化视图模式:

public class LocationModel { 
    public string Street1 { get; set; } 
} 
public class UsLocationModel : LocationModel { 
    public string State { get; set; } 
} 
public class CaLocationModel : LocationModel { 
    public string Providence { get; set; } 
} 
public class AddressModel { 
    public int? Country { get; set; } 
    public UsLocationModel UsLocation { get; set; } 
    public CaLocationModel CaLocation { get; set; } 
} 

这里是我的简化AutoMapper配置:

Mapper.CreateMap<Address, AddressModel>() 
      .Include<UsAddress, AddressModel>() 
      .Include<CanadianAddress, AddressModel>(); 
Mapper.CreateMap<UsAddress, AddressModel>(); 
Mapper.CreateMap<CanadianAddress, AddressModel>(); 
Mapper.CreateMap<Address, LocationModel>() 
      .Include<UsAddress, USLocationModel>() 
      .Include<CanadianAddress, CALocationModel>(); 
Mapper.CreateMap<UsAddress, USLocationModel>(); 
Mapper.CreateMap<CanadianAddress, CALocationModel>(); 

我无法弄清楚如何解决UsLocationCaLocationAddressModel ...

回答

1

我想通了。这里是我的Automapper配置的简化版本:

Mapper.CreateMap<Address, AddressModel>() 
    .Include<UsAddress, AddressModel>() 
    .Include<CanadianAddress, AddressModel>() 
    .ForMember(x => x.USLocation, a => a.Ignore()) 
    .ForMember(x => x.CALocation, a => a.Ignore()) 
    .ForMember(x => x.Country, a => a.ResolveUsing<HaveIdValueResolver<Country, int>>().FromMember(x => x.Country); 
Mapper.CreateMap<UsAddress, AddressModel>() 
    .ForMember(x => x.USLocation, a => a.MapFrom(Mapper.Map<UsAddress, USLocationModel>)) 
    .ForMember(x => x.CALocation, a => a.Ignore()) 
    .ForMember(x => x.Country, a => a.ResolveUsing<HaveIdValueResolver<Country, int>>().FromMember(x => x.Country)); 
Mapper.CreateMap<CanadianAddress, AddressModel>() 
    .ForMember(x => x.USLocation, a => a.Ignore()) 
    .ForMember(x => x.CALocation, a => a.MapFrom(Mapper.Map<CanadianAddress, CALocationModel>)) 
    .ForMember(x => x.Country, a => a.ResolveUsing<HaveIdValueResolver<Country, int>>().FromMember(x => x.Country)); 
Mapper.CreateMap<Address, LocationModel>() 
    .Include<UsAddress, USLocationModel>() 
    .Include<CanadianAddress, CALocationModel>(); 
Mapper.CreateMap<UsAddress, USLocationModel>(); 
Mapper.CreateMap<CanadianAddress, CALocationModel>(); 

这里有一个简单的样品测试:

var usAddress = new FakeUsAddress("111 L St", new FakeState(id: 17)); 
var addressModel = Mapper.Map<UsAddress, AddressModel>(usAddress); 
Assert.IsNotNull(addressModel.USLocationModel); 
Assert.IsNull(addressModel.CALocationModel); 
Assert.AreEqual(usAddress.Street1, addressModel.USLocationModel.Street1); 
Assert.AreEqual(usAddress.State.Id, addressModel.USLocationModel.State); 
Assert.AreEqual(usAddress.Country.Id, addressModel.USLocationModel.Country); 
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