如何在C中的这四种情况下分别在字符串数组中打印出字符串？

Question

我尝试使用这四个符号来代表串的阵列，为了测试他们充分理解他们：

char juices_A[][12] 
char *juices_B[] 
char (*juices_C)[][12] 
char **juices_D 

所以我写这篇文章的代码：

#include <stdio.h> 

int main() { 

    int i_A = 0; 
    char juices_A[][12] = { "dragonfruit", "waterberry", "sharonfruit", }; 
    for (; i_A < 3; i_A++) 
     printf("%s;", juices_A[i_A]); 
    puts(""); 

    int i_B=0; 
    char *juices_B[] = { "dragonfruit", "waterberry", "sharonfruit", }; 
    for (; i_B < 3; i_B++) 
     printf("%s;", juices_B[i_B]); 
    puts(""); 

    int i_C=0; 
    char (*juices_C)[][12] = { "dragonfruit", "waterberry", "sharonfruit", }; 
    for (; i_C < 3; i_C++) 
     printf("%s;", (*juices_C)[i_C]); 
    puts(""); 

    int i_D=0; 
    char **juices_D = { "dragonfruit", "waterberry", "sharonfruit", }; 
    for (; i_D < 3; i_D++) 
     printf("%s;", juices_D[i_D]); 
    puts(""); 

    return 0; 
} 

当我尝试运行代码，它显示：

dragonfruit;waterberry;sharonfruit; 
dragonfruit;waterberry;sharonfruit; 
dragonfruit;waterberry;haronfruit; 

显然第三和第四种情况有一些问题，我想为什么。此外，我可以使用类似*juice++或*juice--？

Answer 1

int i_C=0; 
char (*juices_C)[12] = (char [][12]){ "dragonfruit", "waterberry", "sharonfruit", }; 
for (; i_C < 3; i_C++) 
    printf("%s;", juices_C[i_C]); 
puts(""); 

int i_D=0; 
char **juices_D = (char *[]){ "dragonfruit", "waterberry", "sharonfruit", }; 
for (; i_D < 3; i_D++) 
    printf("%s;", juices_D[i_D]); 
puts("");