2016-11-30 92 views
3

我有一个使用RATIO_TO_REPORT()遗留的SQL查询 - 它不使用开放式访问表,但是这是什么样子:如何在BigQuery中的标准SQL中实现RATIO_TO_REPORT()?

SELECT 
    Mutation_AA, 
    Gene_name, 
    CaseCount, 
    RATIO_TO_REPORT(CaseCount) OVER (PARTITION BY Gene_name) AS ratio 
FROM (
    SELECT 
    COUNT(DISTINCT ID_tumour, 50000) AS CaseCount, 
    Mutation_AA, 
    Gene_name 
    FROM 
    [isb-cgc:COSMIC.grch38_v79] 
    GROUP BY 
    Mutation_AA, 
    Gene_name) 

我试图从传统SQL迁移到标准SQL(在使用BigQuery之前从未使用过SQL),所以提示将非常感谢! THX

回答

3

只需直接计算的比例:

SELECT Mutation_AA, 
     Gene_name, 
     CaseCount, 
     (CaseCount/SUM(CaseCount) OVER (PARTITION BY Gene_name)) AS ratio 
. . . 

你不需要的子查询:

SELECT Mutation_AA, Gene_name, 
     COUNT(DISTINCT ID_tumour, 50000) AS CaseCount, 
     COUNT(DISTINCT ID_tumour, 50000)/SUM(COUNT(DISTINCT ID_tumour, 50000)) OVER (PARTITION BY Gene_Name) as ratio 
FROM [isb-cgc:COSMIC.grch38_v79] 
GROUP BY Mutation_AA, Gene_name ; 
相关问题