功能保持阵列从PHP而不是返回undefinded可变爆炸

Question

的rgborhex功能returing未定义的变量：

function rgborhex($unformatedColor){ 
if(strpos($unformatedColor, "-") == false) { //did not find a - in the color string; is not in rgb form; convert 
    $rgbColor = hextorgb($unformatedColor); 
    $rgbColor = explode("-", $rgbColor); 
    return $rgbColor; 
} 
else { // found a - in the color string; is in rgb form; return 
    $rgbColor = $unformatedColor; 
    $rgbColor = explode("-", $rgbColor); 
    return $rbgColor; 
} 
} 

function hextorgb($hex) { 
if(strlen($hex) == 3) { 
    $hrcolor = hexdec(substr($hex, 0, 1));  //r 
    $hrcolor .= "-" . hexdec(substr($hex, 1, 1)); //g 
    $hrcolor .= "-" . hexdec(substr($hex, 2, 1)); //b 
} 
else if(strlen($hex) == 6) { 
    $hrcolor = hexdec(substr($hex, 0, 2));  //r 
    $hrcolor .= "-" . hexdec(substr($hex, 2, 2)); //g 
    $hrcolor .= "-" . hexdec(substr($hex, 4, 2)); //b 
} 
return $hrcolor; 

}

Answer 1

-return $rbgColor; 
+return $rgbColor; 

只是一个错字在你的第二个return声明:)

---

替代 - 小编辑，更易读IMO：

function rgborhex($unformatedColor) { 
    if (strpos($unformatedColor, '-') === false) { //did not find a - in the color string; is not in rgb form; convert 
     $unformatedColor = hextorgb($unformatedColor); 
    } 

    return explode('-', $unformatedColor); 
} 

Answer 2

请把error_reporting放在E_ALL | E_STRICT。这使得PHP返回比预期更多的错误。