命令提示符中没有输出

Question

我的程序用于生成可接受的密码，除了输入提示之外，它不显示任何输出，它允许我输入密码，但程序立即结束。我在调试器上没有发现错误或警告。想知道是否有人可以给我一些意见。

#include "stdafx.h" 
#include <stdio.h> 
#include <ctype.h> 
#include <string.h> 


int main() 
{ 
    char password[15] = {'\0'}; 
    char search[15] = { '\0' }; 
    int a, b, c, d, e; 
    char punct[] = { '!','@','#','$','%','^','&','*','?','_', '\0' }; 

    printf("Enter your test password: \n"); 
    fgets(password, 15, stdin); 

    a = strnlen(password, 15);//judges length of search between the numbers 2 and 15 
    b = strncmp(password, punct, 10); 
    c = isalpha(strnlen(password,15)); 
    d = isdigit(strnlen(password, 15)); 
    e = a + b + c + d; 

    if (a < 2 || a>15) { 

     printf("Must have exactly 2-15 characters.\n"); 

     if (strncmp(password, punct, 10) == false) {//must have one of the characters included in password 
      printf("Must have character punctutation\n"); 
     } 
     if (isdigit(strnlen(password, 15)) == false) { 
      printf("Must consist of at least one number 0-9.\n"); 
     } 
     if (isalpha(strnlen(password, 15)) == false) { 
      printf("Must consist of at least one letter a-z\n"); 
     } 
     else { 
      printf("You have inputted a legal password!\n"); 
     } 

    } 
     return 0; 
    } 

Answer 1

你没有得到的输出，因为strnlen(password, 15)是2和15之间，使用else部分：

if (a < 2 || a > 15) { 
    ... 
} else { 
    /* your output here */ 
} 

在另一方面：

if (isdigit(strnlen(password, 15)) == false) {

是无稽之谈，isdigit检查一个字符是否是十进制数字，但哟你通过size_t而不是char，isalpha相同。